Show values from a MySQL database table inside a H

2019-01-02 15:03发布

站内问答 / PHP
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I want to retrieve the values from a database table and show them in a html table in a page. I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading. The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number. How can I get it to show all the values from the db in a html table like this:

<table border="1">
  <tr>
    <th>Submission ID</th>
    <th>Form ID</th>
    <th>IP</th>
    <th>Name</th>
    <th>E-mail</th>
    <th>Message</th>
  </tr>
  <tr>
    <td>123456789</td>
    <td>12345</td>
    <td>123.555.789</td>
    <td>John Johnny</td>
    <td>johnny@example.com</td>
    <td>This is the message John sent you</td>
  </tr>
</table>

And then all the other values below 'john'.

10条回答
妖精总统
2楼-- · 2019-01-02 15:15

Example taken from W3Schools: PHP Select Data from MySQL

<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM Persons");

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";

while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysqli_close($con);
?>

It's a good place to learn from!

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姐姐魅力值爆表
3楼-- · 2019-01-02 15:15 
<!DOCTYPE html>
<html>
<head>
<style>
table, th, td {
     border: 1px solid black;
}
</style>
</head>
<center>
<body>

<?php

$con = mysql_connect("localhost","root","");
mysql_select_db("rachna",$con);



$query = "SELECT SUM( Ivalue ) AS RESULT FROM loan WHERE cname = 'A' GROUP BY Iyear";
$result = mysql_query($query) or die(mysql_error());

if (mysql_num_rows($result) > 0) {
     echo "<table><tr><th></th><th>1999</th><th>2000</th><th>2001</th><th>2003</th></tr>";
     echo "<th>A</th>"; 

     //Code for A Customer-------------------------------------------
     while($row =mysql_fetch_array($result)) {
         echo "<th>" . $row['RESULT'] . "</th>";
         }

          echo"<tr></tr>";  

           //COde of B Customer--------------------------------------

         echo "<th>B</th>";
     $query = "SELECT SUM( Ivalue ) AS RESULT FROM loan WHERE cname = 'B' GROUP BY Iyear";
    $result1 = mysql_query($query) or die(mysql_error());


     while($row = mysql_fetch_array($result1)) {
         echo "<th> " . $row["RESULT"]. "</th>";
     }
     echo "</table>";
} else {
     echo "0 results";
}


?>  
</center>
</body>
</html>
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无色无味的生活
4楼-- · 2019-01-02 15:17 
<?php
$mysql_hostname = "localhost";
$mysql_user     = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd             = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database

$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()

echo '<table border=1px>';  // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers

while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}

echo '</table>';  //closing table tag
?>

it would print the table like this just read line by line so that you can understand it easily..

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爱死公子算了
5楼-- · 2019-01-02 15:24

OOP Style : At first connection with database.

<?php
class database
{

 public $host = "localhost";
 public $user = "root";
 public $pass = "";
 public $db   = "db";
 public $link;

 public function __construct()
 {
    $this->connect();
 }

 private function connect()
 {
   $this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
    return $this->link;
 }

 public function select($query)
 {
    $result = $this->link->query($query) or die($this->link->error.__LINE__);

    if($result->num_rows>0)
    {
      return $result;
    } 
    else 
    {
      return false;
    }
}
?>

Then :

    <?php
        $db = new database();

        $query = "select * from data";
        $result = $db->select($query);

        echo "<table>";
         echo "<tr>";
            echo "<th>Name </th>";
            echo "<th>Roll </th>";
         echo "</tr>";
         while($row = mysqli_fetch_array($result)) 
         {
            echo "<tr>";
            echo "<td> $row[name]</td>";
            echo "<td> $row[roll]</td>";
            echo "</tr>";
         }
       echo "</table>";
 ?>
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不流泪的眼
6楼-- · 2019-01-02 15:29

Here is an easy way to fetch data from a MySQL database using PDO.

define("DB_HOST", "localhost");    // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");

try {       // << using Try/Catch() to catch errors!

$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8",DB_USER,DB_PASS);
}catch(PDOException $e){ echo $e->getMessage();}

if($dbc <> true){
    die("<p>There was an error</p>");
}

$print = ""; // assign an empty string 

$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);

if($stmt->execute() <> 0)
{

    $print .= '<table border="1px">';
    $print .= '<tr><th>First name</th>';
    $print .= '<th>Last name</th></tr>';

    while($names = $stmt->fetch()) // loop and display data
    {

        $print .= '<tr>';
        $print .= "<td>{$names->firstname}</td>";
        $print .= "<td>{$names->lastname}</td>";
        $print .= '</tr>';
    }

    $print .= "</table>";
    echo $print;
}
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十年一品温如言
7楼-- · 2019-01-02 15:32

Object-Oriented with PHP/5.6.25 and MySQL/5.7.17 using MySQLi [Dynamic]

Learn more about PHP and the MySQLi Library at PHP.net.

First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjust them to fit your environment, then create a new connection object with new mysqli() and initialize it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:

<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully<br>";
?>

Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().

<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
    echo "<tr>";
    for($i = 0; $i < $queryResult->field_count; $i++){
        echo "<td>$queryRow[$i]</td>";
    }
    echo "</tr>";
}
echo "</table>";
$conn->close();
?>

Any feedback would be much appreciated! Good Luck!

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