I have a cron job that needs to include this file:
require '../includes/common.php';
however, when it is run via the cron job (and not my local testing), the relative path does not work. the cron job runs the following file (on the live server):
/home/username123/public_html/cron/mycronjob.php
and here's the error:
Fatal error: require(): Failed opening required '../includes/common.php'
(include_path='.:/usr/lib/php:/usr/local/lib/php') in
/home/username123/public_html/cron/mycronjob.php on line 2
using the same absolute format as the cron job, common.php
would be located at
/home/username123/public_html/includes/common.php
does that mean i have to replace my line 2 with:
require '/home/username123/public_html/includes/common.php';
?
thanks!
Technically seen the php script is run where cron is located; ex. If cron was in /bin/cron, then this statement would look for common.php in /bin/includes/common.php.
So yeah, you'll probably have to use fullpaths or use set_include_path
An alternative to the solutions which recommend absolute path specification is using a
chdir
in your script. That way, your relative paths will work as expected.For example, to change to the directory of the script:
To change to the parent directory of the script:
And so forth.
It sounds as simple as just some script you are running is setting the include_path and you are including that script. use phpinfo() to check the include_path global vs local setting.
nono. you need to use absolute paths on crons.
what I do is:
If the relative path doesn't work, then it means that the current directory set when the cron tasks are running is not /home/username123/public_html. In such cases, you can only use an absolute path.