Why isn't this a syntax error in python?

Question

Noticed a line in our codebase today which I thought surely would have failed the build with syntax error, but tests were passing so apparently it was actually valid python (in both 2.x and 3).

Whitespace is sometimes not required in the conditional expression:

>>> 1if True else 0
1

It doesn't work if the LHS is a variable:

>>> x = 1
>>> xif True else 0
  File "<stdin>", line 1
    xif True else 0
           ^
SyntaxError: invalid syntax

But it does seem to still work with other types of literals:

>>> {'hello'}if False else 'potato'
'potato'

What's going on here, is it intentionally part of the grammar for some reason? Is this odd quirk a known/documented behaviour?

Answer 1

With my limited knowledge of lexical processing and tokenizing I'd say what you're seeing is that any piece that can be lexical parsed as "different" (i.e. numbers/dictionaries, etc...) from the if are being done so. Most languages ignore spaces and I imagine that Python does the same (excluding, of course indentation levels). Once tokens are generated the grammar itself doesn't care, it most likely looks for an [EXPRESSION] [IF] [EXPRESSION] [ELSE] [EXPRESSION] grouping, which, again with your examples, would work fine.

Answer 2

Whitespace between tokens

Except at the beginning of a logical line or in string literals, the whitespace characters space, tab and formfeed can be used interchangeably to separate tokens. Whitespace is needed between two tokens only if their concatenation could otherwise be interpreted as a different token (e.g., ab is one token, but a b is two tokens).

So in this case, 1if is not a valid token, so the whitespace is optional. The 1 is interpreted as an integer literal of which the if is not a part. So if is interpreted separately and recognized as a keyword.

In xif however, an identifier is recognized, so Python is not able to see that you wanted to do x if there.

Answer 3

The Python lexer generates two tokens for the input 1if: the integer 1 and the keyword if, since no token that begins with a digit can contain the string if. xif, on the other hand, is recognized as a valid identifier; there is no reason to believe that it is an identifier followed by a keyword, and so is passed to the parser as a single token.