Consider the following code:
#include<stdio.h>
int main() {
int i=3, j=4;
scanf("%d c %d",&i,&j);
printf("%d %d",i,j);
return 0;
}
It works if I give 2c3
or 2 c 3
or 2c 3
as input if I have to change the value of variables. What should I do if I want the user to enter the same pattern as I want means if %dc%d
then only 2c3
is acceptable and not 2 c 3
and vice versa if it is %d c %d
?
Whitespace in the format string matches 0 or more whitespace characters in the input.
So
"%d c %d"
expects number, then any amount of whitespace characters, then characterc
, then any amount of whitespace characters and another number at the end."%dc%d"
expects number,c
, number.Also note, that if you use
*
in the format string, it suppresses assignment:%*c
= read 1 character, but don't assign it to any variableSo you can use
"%d%*c c%*c %d"
if you want to force user to enter: number, at least 1 character followed by any amount of whitespace characters,c
, at least 1 character followed by any amount of whitespace characters again and number.If you want to accept
1c2
but not1 c 2
, use the pattern without the space:If you want to accept
1c2
and1 c 2
(and also1 \t \t c \t 2
etc), use the pattern with the space:If you want to accept
1 c 2
but not1c2
, add a fake string containing whitespace:Here the format string
%[ \t]
would mean "read a string that contains any number of space and tab characters"; but using the additional*
, it becomes "expect a string that contains any number of space and tab characters; then discard it"I think I would read the scanf result into different variables (i.e. not reuse
i
andj
) as"%d%s%d"
. Then check the string you got from the %s and if it matches your requirements, use the other variables to overwrite i and j.Force a string parsing first :
Then use sscanf() to convert the strings to int.