I'm trying to chain a series of .bat files using the EXIT /B X
command to return success or failure and &&
and ||
for conditional running of the next .bat (e.g. a.bat && b.bat
).
Regardless of whether I call EXIT /B 0
or anything else to end a.bat, a.bat && b.bat
will call b.bat afterward. My understanding is that EXIT /B 0
should set ERRORLEVEL=0
, which is success, so the &&
should continue. The counterpoint to this is that calling EXIT /B 1
should set ERRORLEVEL=1
which is failure, so the &&
should stop. What am I missing here?
Trivialized example:
For non-batch commands, acting as expected:
C:\> echo test|findstr test>NUL && echo yes
yes
C:\> echo test|findstr test>NUL || echo yes
C:\> echo test|findstr nope>NUL && echo yes
C:\> echo test|findstr nope>NUL || echo yes
yes
Using EXIT /B
always sees a.bat as successful:
C:\> echo @EXIT /B 0 > a.bat
C:\> a.bat && echo yes
yes
C:\> a.bat || echo yes
C:\> echo @EXIT /B 1 > a.bat
C:\> a.bat && echo yes
yes
C:\> a.bat || echo yes
How can I exit from a.bat so that a.bat && b.bat
and a.bat || b.bat
behave as expected?
All commands are run in cmd.exe on Windows XP SP3.
I think you are getting
Errorlevel=0
with because you are indeed executing a.bat (regardless of the return code).You would fail the check if
a.bat
did not exist.CALL
is the only way I know to pull in the environment froma.bat
.It works as it should when using call to execute batch scripts containing an exit statement:
By the way, it says wrongly on Microsoft docs:
If you ask me, exit codes in batch files are broken for this exact reason, but there is a hacky workaround you can use. As the last line of your batch file, use:
Since this is an actual process that is started you get a real process exit code and && and || will work.
If you use
start /wait
you can also use this in a very simple Windows application (written in C#) called by DOS batch files like so:Then the application can be called by your DOS batch file and evaluate the result. i.e.
NOTE: the
/wait
is not necessary in a batch file.You could pass in the return code you want as an argument to your program.cs and get it out this way guaranteed.