Why is [1,2] + [3,4] = “1,23,4” in JavaScript?

2019-01-01 14:33发布

I wanted to add the elements of an array into another, so I tried this:

[1,2] + [3,4]

It responded with:

"1,23,4"

What is going on?

13条回答
妖精总统
2楼-- · 2019-01-01 14:55

JavaScript's + operator has two purposes: adding two numbers, or joining two strings. It doesn't have a specific behaviour for arrays, so it's converting them to strings and then joining them.

If you want to join two arrays to produce a new one, use the .concat method instead:

[1, 2].concat([3, 4]) // [1, 2, 3, 4]

If you want to efficiently add all elements from one array to another, you need to use the .push method:

var data = [1, 2];

// ES6+:
data.push(...[3, 4]);
// or legacy:
Array.prototype.push.apply(data, [3, 4]);

// data is now [1, 2, 3, 4]

The behaviour of the + operator is defined in ECMA-262 5e Section 11.6.1:

11.6.1 The Addition operator ( + )

The addition operator either performs string concatenation or numeric addition. The production AdditiveExpression : AdditiveExpression + MultiplicativeExpression is evaluated as follows:

  1. Let lref be the result of evaluating AdditiveExpression.
  2. Let lval be GetValue(lref).
  3. Let rref be the result of evaluating MultiplicativeExpression.
  4. Let rval be GetValue(rref).
  5. Let lprim be ToPrimitive(lval).
  6. Let rprim be ToPrimitive(rval).
  7. If Type(lprim) is String or Type(rprim) is String, then
    1. Return the String that is the result of concatenating ToString(lprim) followed by ToString(rprim)
  8. Return the result of applying the addition operation to ToNumber(lprim) and ToNumber(rprim). See the Note below 11.6.3.

You can see that each operand is converted ToPrimitive. By reading further we can find that ToPrimitive will always convert arrays to strings, producing this result.

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临风纵饮
3楼-- · 2019-01-01 14:56

The + operator is not defined for arrays.

What happens is that Javascript converts arrays into strings and concatenates those.

 

Update

Since this question and consequently my answer is getting a lot of attention I felt it would be useful and relevant to have an overview about how the + operator behaves in general also.

So, here it goes.

Excluding E4X and implementation-specific stuff, Javascript (as of ES5) has 6 built-in data types:

  1. Undefined
  2. Null
  3. Boolean
  4. Number
  5. String
  6. Object

Note that although typeof somewhat confusingly returns object for Null and function for callable Objects, Null is actually not an Object and strictly speaking, in specification-conforming Javascript implementations all functions are considered to be Objects.

That's right - Javascript has no primitive arrays as such; only instances of an Object called Array with some syntactic sugar to ease the pain.

Adding more to the confusion, wrapper entities such as new Number(5), new Boolean(true) and new String("abc") are all of object type, not numbers, booleans or strings as one might expect. Nevertheless for arithmetic operators Number and Boolean behave as numbers.

Easy, huh? With all that out of the way, we can move on to the overview itself.

Different result types of + by operand types

            || undefined | null   | boolean | number | string | object |
=========================================================================
 undefined  || number    | number | number  | number | string | string | 
 null       || number    | number | number  | number | string | string | 
 boolean    || number    | number | number  | number | string | string | 
 number     || number    | number | number  | number | string | string | 
 string     || string    | string | string  | string | string | string | 
 object     || string    | string | string  | string | string | string | 

* applies to Chrome13, FF6, Opera11 and IE9. Checking other browsers and versions is left as an exercise for the reader.

Note: As pointed out by CMS, for certain cases of objects such as Number, Boolean and custom ones the + operator doesn't necessarily produce a string result. It can vary depending on the implementation of object to primitive conversion. For example var o = { valueOf:function () { return 4; } }; evaluating o + 2; produces 6, a number, evaluating o + '2' produces '42', a string.

To see how the overview table was generated visit http://jsfiddle.net/1obxuc7m/

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刘海飞了
4楼-- · 2019-01-01 14:56

It's doing exactly what you asked it to do.

What you're adding together are array references (which JS converts to strings), not numbers as it seems. It's a bit like adding strings together: "hello " + "world" = "hello world"

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回忆,回不去的记忆
5楼-- · 2019-01-01 14:56

Another result using just a simple "+" sign will be:

[1,2]+','+[3,4] === [1,2,3,4]

So something like this should work (but!):

var a=[1,2];
var b=[3,4];
a=a+','+b; // [1,2,3,4]

... but it will convert the variable a from an Array to String! Keep it in mind.

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呛了眼睛熬了心
6楼-- · 2019-01-01 14:59

In JavaScript, the binary addition operator (+) performs both numerical addition and string concatenation. However, when it's first argument is neither a number nor a string then it converts it into a string (hence "1,2") then it does the same with the second "3,4" and concatenates them to "1,23,4".

Try using the "concat" method of Arrays instead:

var a = [1, 2];
var b = [3, 4];
a.concat(b) ; // => [1, 2, 3, 4];
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冷夜・残月
7楼-- · 2019-01-01 15:03

would be nice if you could overload operators in JavaScript but you can't: Can I define custom operator overloads in Javascript? you can only hack the "==" operator which converts to strings before comparing: http://blogger.xs4all.nl/peterned/archive/2009/04/01/462517.aspx

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