How to return only the Date from a SQL Server Date

Question

SELECT GETDATE()

Returns: 2008-09-22 15:24:13.790

I want that date part without the time part: 2008-09-22 00:00:00.000

How can I get that?

Answer 1

I think this would work in your case:

CONVERT(VARCHAR(10),Person.DateOfBirth,111) AS BirthDate
//here date is obtained as 1990/09/25

Answer 2

why don't you use DATE_FORMAT( your_datetiem_column, '%d-%m-%Y' ) ?

EX: select DATE_FORMAT( some_datetime_column, '%d-%m-%Y' ) from table_name

you can change sequence of m,d and year by re-arranging '%d-%m-%Y' part

Answer 3

You can use the CONVERT function to return only the date. See the link(s) below:

Date and Time Manipulation in SQL Server 2000

CAST and CONVERT

The syntax for using the convert function is:

CONVERT ( data_type [ ( length ) ] , expression [ , style ] ) 

Answer 4

Date:

SELECT CONVERT(date, GETDATE())
SELECT CAST(GETDATE() as date)

Time:

SELECT CONVERT(time , GETDATE() , 114)
SELECT CAST(GETDATE() as time)

Answer 5

Even using the ancient MSSQL Server 7.0, the code here (courtesy of this link) allowed me to get whatever date format I was looking for at the time:

PRINT '1) Date/time in format MON DD YYYY HH:MI AM (OR PM): ' + CONVERT(CHAR(19),GETDATE())  
PRINT '2) Date/time in format MM-DD-YY: ' + CONVERT(CHAR(8),GETDATE(),10)  
PRINT '3) Date/time in format MM-DD-YYYY: ' + CONVERT(CHAR(10),GETDATE(),110) 
PRINT '4) Date/time in format DD MON YYYY: ' + CONVERT(CHAR(11),GETDATE(),106)
PRINT '5) Date/time in format DD MON YY: ' + CONVERT(CHAR(9),GETDATE(),6) 
PRINT '6) Date/time in format DD MON YYYY HH:MM:SS:MMM(24H): ' + CONVERT(CHAR(24),GETDATE(),113)

It produced this output:

1) Date/time in format MON DD YYYY HH:MI AM (OR PM): Feb 27 2015  1:14PM
2) Date/time in format MM-DD-YY: 02-27-15
3) Date/time in format MM-DD-YYYY: 02-27-2015
4) Date/time in format DD MON YYYY: 27 Feb 2015
5) Date/time in format DD MON YY: 27 Feb 15
6) Date/time in format DD MON YYYY HH:MM:SS:MMM(24H): 27 Feb 2015 13:14:46:630

Answer 6

Starting from SQL SERVER 2012, you can do this:

SELECT FORMAT(GETDATE(), 'yyyy-MM-dd 00:00:00.000')