django most efficient way to count same field valu

Question

Lets say if I have a model that has lots of fields, but I only care about a charfield. Lets say that charfield can be anything so I don't know the possible values, but I know that the values frequently overlap. So I could have 20 objects with "abc" and 10 objects with "xyz" or I could have 50 objects with "def" and 80 with "stu" and i have 40000 with no overlap which I really don't care about.

How do I count the objects efficiently? What I would like returned is something like:

{'abc': 20, 'xyz':10, 'other': 10,000}

or something like that, w/o making a ton of SQL calls.

EDIT:

I dont know if anyone will see this since I am editing it kind of late, but...

I have this model:

class Action(models.Model):
    author = models.CharField(max_length=255)
    purl = models.CharField(max_length=255, null=True)

and from the answers, I have done this:

groups = Action.objects.filter(author='James').values('purl').annotate(count=Count('purl'))

but...

this is what groups is:

{"purl": "waka"},{"purl": "waka"},{"purl": "waka"},{"purl": "waka"},{"purl": "mora"},{"purl": "mora"},{"purl": "mora"},{"purl": "mora"},{"purl": "mora"},{"purl": "lora"}

(I just filled purl with dummy values)

what I want is

{'waka': 4, 'mora': 5, 'lora': 1}

Hopefully someone will see this edit...

EDIT 2:

Apparently my database (BigTable) does not support the aggregate functions of Django and this is why I have been having all the problems.

Answer 1

This is called aggregation, and Django supports it directly.

You can get your exact output by filtering the values you want to count, getting the list of values, and counting them, all in one set of database calls:

from django.db.models import Count
MyModel.objects.filter(myfield__in=('abc', 'xyz')).\
        values('myfield').annotate(Count('myfield'))

Answer 2

Unless your field value is always guaranteed to be in a specific case, it may be useful to transform it prior to performing a count, i.e. so 'apple' and 'Apple' would be treated as the same.

from django.db.models import Count
from django.db.models.functions import Lower

MyModel.objects.annotate(lower_title=Lower('title')).values('lower_title').annotate(num=Count('lower_title')).order_by('num')

Answer 3

You can use Django's Count aggregation on a queryset to accomplish this. Something like this:

from django.db.models import Count
queryset = MyModel.objects.all().annotate(count = Count('my_charfield'))
for each in queryset:
    print "%s: %s" % (each.my_charfield, each.count)

Answer 4

You want something similar to "count ... group by". You can do this with the aggregation features of django's ORM:

from django.db.models import Count

fieldname = 'myCharField'
MyModel.objects.values(fieldname)
    .order_by(fieldname)
    .annotate(the_count=Count(fieldname))

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