This question already has an answer here:
Here's my Web.xml
dispatcherServlet org.springframework.web.servlet.DispatcherServlet contextConfigLocation /WEB-INF/spring/servlet-context.xml 1
<servlet-mapping>
<servlet-name>dispatcherServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
my servlet-context.xml
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
And lastly the Handler class. which is under com.springexample.controller.impl
@Controller
public class IndexControllerImpl implements IndexController {
@RequestMapping("/")
public String index() {
return "index";
}
}
However on going to localhost:8080/projectname/
it returns a 404 error.
Jul 27, 2013 8:18:31 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/tasklist/WEB-INF/views/index.jsp] in DispatcherServlet with name 'dispatcherServlet'
Jul 27, 2013 8:18:37 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/tasklist/index] in DispatcherServlet with name '
Here is my project structure
With the web.xml configured they way you have in the question, in particular:
ALL requests being made to your web app will be directed to the
DispatcherServlet
. This includes requests like/tasklist/
,/tasklist/some-thing.html
,/tasklist/WEB-INF/views/index.jsp
.Because of this, when your controller returns a view that points to a
.jsp
, instead of allowing your server container to service the request, theDispatcherServlet
jumps in and starts looking for a controller that can service this request, it doesn't find any and hence the404
.The simplest way to solve is to have your servlet url mapping as follows:
Notice the missing
*
. This tells the container that any request that does not have apath info
in it (urls without a .xxx at the end), should be sent to theDispatcherServlet
. With this configuration, when axxx.jsp
request is received, theDispatcherServlet
is not consulted, and your servlet container's default servlet will service the request and present the jsp as expected.Hope this helps, I realize your earlier comments state that the problem has been resolved, but the solution CAN NOT be just adding
method=RequestMethod.GET
to theRequestMethod
.I have the same problem.... I change my project name and i have this problem...my solution was the checking project refences and use
/
in my web.xml (instead of/*
)I added META-INF folder with context.xml contain
SpringGradleDemo is my project name and it work. My servlet-mapping is "/" I read it here https://tomcat.apache.org/tomcat-5.5-doc/config/context.html
change to:
First check whether the java classes are compiled or not in your [PROJECT_NAME]\target\classes directory.
If not you have some compilation errors in your java classes.
Try passing the Model object in your index method and it will work-
Actually the spring container looks for a Model object in the mapping method. If it finds the same it will pass the returning String as view to the View resolver.
Hope this helps.