Twitter OAuth and accessToken to GET statuses/user

Question

I'm trying to acquire the accessToken value from Twitter for using it in my app (I need to use API v1.1's Authentication Model for GET statuses/user_timeline); I have registered my app on api.twitter.com, imported the AFOAuth1Client classes in the project, and this is the simple code:

- (void)viewDidLoad
{
    self.twitterClient = [[AFOAuth1Client alloc] initWithBaseURL:
                                     [NSURL URLWithString:@"https://api.twitter.com/"] key:@"MYKEY" secret:@"MYSECRETKEY"];
    AFOAuth1Token *accessToken;

    [self.twitterClient acquireOAuthAccessTokenWithPath:@"oauth/request_token" requestToken:accessToken accessMethod:@"GET" success:^(AFOAuth1Token *accessToken) { // I have tried also accessMethod: @"POST"
        NSLog(@"Success: %@", accessToken);
    } failure:^(NSError *error) {
        NSLog(@"Error: %@", error);
    }];
}

Unluckly XCode give me this error:

Error: Error Domain=AFNetworkingErrorDomain Code=-1011 "Expected status code in (200-299), got 401" UserInfo=0x79a14f0 {NSLocalizedRecoverySuggestion=Failed to validate oauth signature and token, AFNetworkingOperationFailingURLResponseErrorKey=<NSHTTPURLResponse: 0x7956390>

What is wrong here? DO i need to REGISTER app on api.twitter.com? Is it the right way, or, what is the simpler way to Get statuses/user_timeline using API v1.1's Twitter Authentication Model in iOS? Thank you!

EDIT: possible waypoint?

1) register a new app on dev.twitter.com

2) in OAuth settings, read Consumer key and Consumer secret

3) set default app access type to read? or read/write? ask for access tokens? use this values in.... ?

Answer 1

You probably want to use the iOS built-in Twitter framework instead.

See Apple's Tweeting sample code.

Answer 2

If you have your own consumer tokens, you can use the STTwitter library I wrote.

STTwitterAPI *twitter =
  [STTwitterAPI twitterAPIWithOAuthConsumerName:@""
                                    consumerKey:@"your_key"
                                 consumerSecret:@"your_secret"
                                       username:@"username"
                                       password:@"password"];

[twitter verifyCredentialsWithSuccessBlock:^(NSString *username) {

    NSLog(@"Access granted for %@", username);

    [twitter getUserTimelineWithScreenName:@"barackobama"
                              successBlock:^(NSArray *statuses) {
        NSLog(@"-- statuses: %@", statuses);
    } errorBlock:^(NSError *error) {
        NSLog(@"-- error: %@", error);
    }];

} errorBlock:^(NSError *error) {
    NSLog(@"-- error %@", error);
}];

If your tokens are not 'xAuth' enabled, you'll have to use a PIN. STTwitter provides simple asynchronous block-based methods to ask the user. You can also choose to automate the PIN retrieval, see STTwitterDemo -[AppDelegate guessPIN:] for an automated process.

Answer 3

STTwitter is simple for use . Also I added example that you can get public twitter timeline

Answer 4

It's been a few days since Twitter added an application only mode. In this mode, you can access specific API endpoints without user's context, ie. your users don't have to authenticate. Only the application does authenticate once in a while to get a "bearer token" which is then sent in every request.

The following code gets a bearer token and then retrieves the public timeline for @barackobama.

STTwitterAPI *twitter = [STTwitterAPI twitterAPIApplicationOnlyWithConsumerKey:@""
                                                                consumerSecret:@""];

[twitter verifyCredentialsWithSuccessBlock:^(NSString *bearerToken) {

    NSLog(@"Access granted with %@", bearerToken);

    [twitter getUserTimelineWithScreenName:@"barackobama" successBlock:^(NSArray *statuses) {
        NSLog(@"-- statuses: %@", statuses);
    } errorBlock:^(NSError *error) {
        NSLog(@"-- error: %@", error);
    }];

} errorBlock:^(NSError *error) {
    NSLog(@"-- error %@", error);
}];

See STTwitter iOS demo project for a working example (use you own consumer key / secret).