JavaScript math, round to two decimal places [dupl

Question

This question already has an answer here:

• Round to at most 2 decimal places (only if necessary) 59 answers

I have the following JavaScript syntax:

var discount = Math.round(100 - (price / listprice) * 100);

This rounds up to the whole number. How can I return the result with two decimal places?

Answer 1

NOTE - See Edit 4 if 3 digit precision is important

var discount = (price / listprice).toFixed(2);

toFixed will round up or down for you depending on the values beyond 2 decimals.

Example: http://jsfiddle.net/calder12/tv9HY/

Documentation: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toFixed

Edit - As mentioned by others this converts the result to a string. To avoid this:

var discount = +((price / listprice).toFixed(2));

Edit 2- As also mentioned in the comments this function fails in some precision, in the case of 1.005 for example it will return 1.00 instead of 1.01. If accuracy to this degree is important I've found this answer: https://stackoverflow.com/a/32605063/1726511 Which seems to work well with all the tests I've tried.

There is one minor modification required though, the function in the answer linked above returns whole numbers when it rounds to one, so for example 99.004 will return 99 instead of 99.00 which isn't ideal for displaying prices.

Edit 3 - Seems having the toFixed on the actual return was STILL screwing up some numbers, this final edit appears to work. Geez so many reworks!

   var discount = roundTo((price / listprice), 2);

   function roundTo(n, digits) {
     if (digits === undefined) {
       digits = 0;
     }

     var multiplicator = Math.pow(10, digits);
     n = parseFloat((n * multiplicator).toFixed(11));
     var test =(Math.round(n) / multiplicator);
     return +(test.toFixed(digits));
   }

See Fiddle example here: https://jsfiddle.net/calder12/3Lbhfy5s/

Edit 4 - You guys are killing me. Edit 3 fails on negative numbers, without digging into why it's just easier to deal with turning a negative number positive before doing the rounding, then turning it back before returning the result.

function roundTo(n, digits) {
    var negative = false;
    if (digits === undefined) {
        digits = 0;
    }
        if( n < 0) {
        negative = true;
      n = n * -1;
    }
    var multiplicator = Math.pow(10, digits);
    n = parseFloat((n * multiplicator).toFixed(11));
    n = (Math.round(n) / multiplicator).toFixed(2);
    if( negative ) {    
        n = (n * -1).toFixed(2);
    }
    return n;
}

Fiddle: https://jsfiddle.net/3Lbhfy5s/79/

Answer 2

If you use a unary plus to convert a string to a number as documented on MDN.

For example:+discount.toFixed(2)

Answer 3

Fastest Way - faster than toFixed():

TWO DECIMALS

x      = .123456
result = Math.round(x * 100) / 100  // result .12

---

THREE DECIMALS

x      = .123456
result = Math.round(x * 1000) / 1000      // result .123

Answer 4

try using discount.toFixed(2);

Answer 5

A small variation on the accepted answer. toFixed(2) returns a string, and you will always get two decimal places. These might be zeros. If you would like to suppress final zero(s), simply do this:

var discount = + ((price / listprice).toFixed(2));

Edited: I've just discovered what seems to be a bug in Firefox 35.0.1, which means that the above may give NaN with some values.
I've changed my code to

var discount = Math.round(price / listprice * 100) / 100;

This gives a number with up to two decimal places. If you wanted three, you would multiply and divide by 1000, and so on.
The OP wants two decimal places always, but if toFixed() is broken in Firefox it needs fixing first.
See https://bugzilla.mozilla.org/show_bug.cgi?id=1134388

Answer 6

I think the best way I've seen it done is multiplying by 10 to the power of the number of digits, then doing a Math.round, then finally dividing by 10 to the power of digits. Here is a simple function I use in typescript:

function roundToXDigits(value: number, digits: number) {
    value = value * Math.pow(10, digits);
    value = Math.round(value);
    value = value / Math.pow(10, digits);
    return value;
}

Or plain javascript:

function roundToXDigits(value, digits) {
    if(!digits){
        digits = 2;
    }
    value = value * Math.pow(10, digits);
    value = Math.round(value);
    value = value / Math.pow(10, digits);
    return value;
}