SET versus SELECT when assigning variables?

2019-01-01 11:50发布

What are the differences between the SET and SELECT statements when assigning variables in T-SQL?

3条回答
呛了眼睛熬了心
2楼-- · 2019-01-01 12:33

Quote, which summarizes from this article:

  1. SET is the ANSI standard for variable assignment, SELECT is not.
  2. SET can only assign one variable at a time, SELECT can make multiple assignments at once.
  3. If assigning from a query, SET can only assign a scalar value. If the query returns multiple values/rows then SET will raise an error. SELECT will assign one of the values to the variable and hide the fact that multiple values were returned (so you'd likely never know why something was going wrong elsewhere - have fun troubleshooting that one)
  4. When assigning from a query if there is no value returned then SET will assign NULL, where SELECT will not make the assignment at all (so the variable will not be changed from its previous value)
  5. As far as speed differences - there are no direct differences between SET and SELECT. However SELECT's ability to make multiple assignments in one shot does give it a slight speed advantage over SET.
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不流泪的眼
3楼-- · 2019-01-01 12:40

When writing queries, this difference should be kept in mind :

DECLARE @A INT = 2

SELECT  @A = TBL.A
FROM    ( SELECT 1 A ) TBL
WHERE   1 = 2

SELECT  @A
/* @A is 2*/

---------------------------------------------------------------

DECLARE @A INT = 2

SET @A = ( 
            SELECT  TBL.A
            FROM    ( SELECT 1 A) TBL
            WHERE   1 = 2
         )

SELECT  @A
/* @A is null*/
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梦该遗忘
4楼-- · 2019-01-01 12:44

I believe SET is ANSI standard whereas the SELECT is not. Also note the different behavior of SET vs. SELECT in the example below when a value is not found.

declare @var varchar(20)
set @var = 'Joe'
set @var = (select name from master.sys.tables where name = 'qwerty')
select @var /* @var is now NULL */

set @var = 'Joe'
select @var = name from master.sys.tables where name = 'qwerty'
select @var /* @var is still equal to 'Joe' */
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