Can uglify-js remove the console.log statements?

2019-01-16 16:02发布

I'm using uglify-js to minify the source code. I want to remove the console.log statements of the original source code. Is it possible? Or is there any other compressor tool supports this?

I use the code as below in Node.js.

var uglify = require('uglify-js');
var originalSourceCode = 'var name = function(){var str = "test"; return str}; console.log("log data");';
var minifiedCode = uglify.minify(originalSourceCode, {
                fromString : true,
                mangle: {},
                warnings: true
            });
console.log(minifiedCode);

The output is:

$node m.js
{ code: 'var name=function(){var a="test";return a};console.log("log data");',
  map: 'null' }

In the minified code the console.log isn't removed.

5条回答
甜甜的少女心
2楼-- · 2019-01-16 16:33

There's also another option called drop_console which has been added recently (late 2013)

drop_console -- default false. Pass true to discard calls to console.* functions

This is added to the grunt init config like this:

grunt.initConfig({
  uglify: {
    options: {
      compress: {
        drop_console: true // <-
      }
    },
    my_target: {
      files: {
        'dest/output.min.js': ['src/input.js']
      }
    }
  }
});

As taken from the grunt-contrib-uglify github documents

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趁早两清
3楼-- · 2019-01-16 16:35

In the lastest uglify-js ( v2.4.3), a new compress option ‘pure_funcs’ is added. If I add the console.log functions to this array, it will be removed in the minified js file. The test code below shows how this option works. This is exactly what I want.

// file: m.js
var uglify = require('uglify-js');
var originalSourceCode = 'var name = function(){var str = "test"; return str}; console.log("log data" + name());';
var minifiedCode = uglify.minify(originalSourceCode, {
                fromString : true,
                mangle: {},
                warnings: true,
                compress:{
                    pure_funcs: [ 'console.log' ]
                }
            });
console.log(minifiedCode);

$node m.js
WARN: Dropping side-effect-free statement [?:1,53]
{ code: 'var name=function(){var n="test";return n};',
  map: 'null' }

Quotes from https://github.com/mishoo/UglifyJS2

pure_funcs -- default null. You can pass an array of names and UglifyJS will assume that those functions do not produce side effects. DANGER: will not check if the name is redefined in scope. An example case here, for instance var q = Math.floor(a/b). If variable q is not used elsewhere, UglifyJS will drop it, but will still keep the Math.floor(a/b), not knowing what it does. You can pass pure_funcs: [ 'Math.floor' ] to let it know that this function won't produce any side effect, in which case the whole statement would get discarded. The current implementation adds some overhead (compression will be slower).

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爷、活的狠高调
4楼-- · 2019-01-16 16:41

If you are using gulp, use 'gulp-strip-debug' to remove console, alert and debugger. https://www.npmjs.com/package/gulp-strip-debug

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一夜七次
5楼-- · 2019-01-16 16:46

You can use Groundskeeper to do this though it will be a separate step.

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Animai°情兽
6楼-- · 2019-01-16 16:57

for -c option, set drop_console to be true: uglifyjs app.js -m -c drop_console=true -o app.min.js

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