Check whether variable is number or string in Java

Question

Does anyone know how can I check whether a variable is a number or a string in JavaScript?

Answer 1

Check if the value is a string literal or String object:

function isString(o) {
    return typeof o == "string" || (typeof o == "object" && o.constructor === String);
}

Unit test:

function assertTrue(value, message) {
    if (!value) {
        alert("Assertion error: " + message);
    }
}

function assertFalse(value, message)
{
    assertTrue(!value, message);
}

assertTrue(isString("string literal"), "number literal");
assertTrue(isString(new String("String object")), "String object");
assertFalse(isString(1), "number literal");
assertFalse(isString(true), "boolean literal");
assertFalse(isString({}), "object");

Checking for a number is similar:

function isNumber(o) {
    return typeof o == "number" || (typeof o == "object" && o.constructor === Number);
}

Answer 2

Errr? Just use regular expressions! :)

function isInteger(val) {
  return val.match(/^[0-9]$/)
}

function isFloat(val) {
  return val.match(/^[0-9]*/\.[0-9]+$/)
}

Answer 3

What do you thing about this one?

const numberOrString='10' 
const isNumber = !isNaN(numberOrString*1) 

Answer 4

typeof works very well for me in most case. You can try using an if statement

if(typeof x === 'string' || typeof x === 'number') {
    console.log("Your statement");
}

where x is any variable name of your choice

Answer 5

Best way to do that is using isNaN + type casting:

Updated all-in method:

function isNumber(n) { return !isNaN(parseFloat(n)) && !isNaN(n - 0) }

The same using regex:

function isNumber(n) { return /^-?[\d.]+(?:e-?\d+)?$/.test(n); } 

------------------------

isNumber ('123'); // true  
isNumber ('123abc'); // true  
isNumber (5); // true  
isNumber ('q345'); // false
isNumber(null); // false
isNumber(undefined); // false
isNumber(false); // false
isNumber('   '); // false

Answer 6

Best way to do this:

function isNumber(num) {
  return (typeof num == 'string' || typeof num == 'number') && !isNaN(num - 0) && num !== '';
};

This satisfies the following test cases:

assertEquals("ISNUMBER-True: 0", true, isNumber(0));
assertEquals("ISNUMBER-True: 1", true, isNumber(-1));
assertEquals("ISNUMBER-True: 2", true, isNumber(-500));
assertEquals("ISNUMBER-True: 3", true, isNumber(15000));
assertEquals("ISNUMBER-True: 4", true, isNumber(0.35));
assertEquals("ISNUMBER-True: 5", true, isNumber(-10.35));
assertEquals("ISNUMBER-True: 6", true, isNumber(2.534e25));
assertEquals("ISNUMBER-True: 7", true, isNumber('2.534e25'));
assertEquals("ISNUMBER-True: 8", true, isNumber('52334'));
assertEquals("ISNUMBER-True: 9", true, isNumber('-234'));

assertEquals("ISNUMBER-False: 0", false, isNumber(NaN));
assertEquals("ISNUMBER-False: 1", false, isNumber({}));
assertEquals("ISNUMBER-False: 2", false, isNumber([]));
assertEquals("ISNUMBER-False: 3", false, isNumber(''));
assertEquals("ISNUMBER-False: 4", false, isNumber('one'));
assertEquals("ISNUMBER-False: 5", false, isNumber(true));
assertEquals("ISNUMBER-False: 6", false, isNumber(false));
assertEquals("ISNUMBER-False: 7", false, isNumber());
assertEquals("ISNUMBER-False: 8", false, isNumber(undefined));
assertEquals("ISNUMBER-False: 9", false, isNumber(null));