Python Sendgrid send email with PDF attachment fil

2020-08-25 04:19发布

I'm trying to attach a PDF file to my email sent with sendgrid.

Here is my code :

sg = sendgrid.SendGridAPIClient(apikey=os.environ.get('SENDGRID_API_KEY'))

from_email = Email("from@example.com")
subject = "subject"
to_email = Email("to@example.com")
content = Content("text/html", email_body)

pdf = open(pdf_path, "rb").read().encode("base64")
attachment = Attachment()
attachment.set_content(pdf)
attachment.set_type("application/pdf")
attachment.set_filename("test.pdf")
attachment.set_disposition("attachment")
attachment.set_content_id(number)

mail = Mail(from_email, subject, to_email, content)
mail.add_attachment(attachment)

response = sg.client.mail.send.post(request_body=mail.get())

print(response.status_code)
print(response.body)
print(response.headers)

But the Sendgrid Python library is throwing an error HTTP Error 400: Bad Request.

What is wrong with my code ?

3条回答
The star\"
2楼-- · 2020-08-25 04:36

I found a solution. I replaced this line :

pdf = open(pdf_path, "rb").read().encode("base64")

By this :

with open(pdf_path, 'rb') as f:
    data = f.read()

encoded = base64.b64encode(data)

Now it works. I can send encoded file in the set_content :

attachment.set_content(encoded)

Note: The answer above works for Sendgrid v2 or lower. For v3 and up use:

encoded = base64.b64encode(data).decode()
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Bombasti
3楼-- · 2020-08-25 04:36

This is my solution, Works with Sendgrid V3

    # Where it was uploaded Path.
    file_path = "MY_FILE_PATH"

    with open(file_path, 'rb') as f:
        data = f.read()

    # Encode contents of file as Base 64
    encoded = base64.b64encode(data).decode()

    """Build attachment"""
    attachment = Attachment()
    attachment.content = encoded
    attachment.type = "application/pdf"
    attachment.filename = "my_pdf_attachment.pdf"
    attachment.disposition = "attachment"
    attachment.content_id = "PDF Document file"

    sg = sendgrid.SendGridAPIClient(apikey=settings.SENDGRID_API_KEY)

    from_email = Email("origin@gmail.com")
    to_email = Email('recipient@gmail.com')
    content = Content("text/html", html_content)

    mail = Mail(from_email, 'Attachment mail PDF', to_email, content)
    mail.add_attachment(attachment)

    try:
        response = sg.client.mail.send.post(request_body=mail.get())
    except urllib.HTTPError as e:
        print(e.read())
        exit()
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我欲成王,谁敢阻挡
4楼-- · 2020-08-25 04:48

Straight from the Sendgrid docs:

import urllib.request as urllib
import base64
import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import (Mail, Attachment, FileContent, FileName, FileType, Disposition, ContentId)

import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail

message = Mail(
    from_email='from_email@example.com',
    to_emails='to@example.com',
    subject='Sending with Twilio SendGrid is Fun',
    html_content='<strong>and easy to do anywhere, even with Python</strong>')
file_path = 'example.pdf'
with open(file_path, 'rb') as f:
    data = f.read()
    f.close()
encoded = base64.b64encode(data).decode()
attachment = Attachment()
attachment.file_content = FileContent(encoded)
attachment.file_type = FileType('application/pdf')
attachment.file_name = FileName('test_filename.pdf')
attachment.disposition = Disposition('attachment')
attachment.content_id = ContentId('Example Content ID')
message.attachment = attachment
try:
    sendgrid_client = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
    response = sendgrid_client.send(message)
    print(response.status_code)
    print(response.body)
    print(response.headers)
except Exception as e:
    print(e.message)
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