Number of seconds since the beginning of the day U

2020-08-13 05:44发布

How do I find "number of seconds since the beginning of the day UTC timezone" in Python? I looked at the docs and didn't understand how to get this using datetime.timedelta.

3条回答
走好不送
2楼-- · 2020-08-13 05:58

Here's one way to do it.

from datetime import datetime, time

utcnow = datetime.utcnow()
midnight_utc = datetime.combine(utcnow.date(), time(0))
delta = utcnow - midnight_utc
print delta.seconds # <-- careful

EDIT As suggested, if you want microsecond precision, or potentially crossing a 24-hour period (i.e. delta.days > 0), use total_seconds() or the formula given by @unutbu.

print delta.total_seconds()  # 2.7
print delta.days * 24 * 60 * 60 + delta.seconds + delta.microseconds / 1e6 # < 2.7
查看更多
Viruses.
3楼-- · 2020-08-13 06:16

The number of seconds in a datetime.timedelta, x, is given by timedelta.total_seconds:

x.total_seconds()

This function was introduced in Python2.7. For older versions of python, you just have to compute it yourself: total_seconds = x.days*24*60*60 + x.seconds + x.microseconds/1e6.

查看更多
在下西门庆
4楼-- · 2020-08-13 06:23
import time
t = time.gmtime()
seconds_since_utc_midnight = t.tm_sec + (t.tm_min * 60) + (t.tm_hour * 3600)

for localtime, we can use time.localtime() instead of time.gmtime()

查看更多
登录 后发表回答