Change UISegmentedControl selected index or value

2020-08-09 08:18发布

I have a UISegmentedControl with two segments (index: 0 and 1) that I am trying to reset programmatically to 0. When I run the command below it does not reset the segment index to 0 as expected. Instead it highlights segment indexed 1.

    [seg setSelectedSegmentIndex:0];

Oddly when I log the selected segment, it returns 0.

    NSLog(@"seg setSelectedSegmentIndex %d", seg.selectedSegmentIndex); 

Also oddly, after running setSelectedSegmentIndex:0 I cannot reselect segment 0 manually by touch, it seems to be locked to segment 1, until I tap 1 wherein it works as normal.

Here is the setup for the button:

    itemArray = [NSMutableArray arrayWithObjects: @"Zero", @"One", nil];
    seg = [[UISegmentedControl alloc] initWithItems:itemArray];
    [seg setFrame:segRect];
    seg.segmentedControlStyle = UISegmentedControlStyleBar;
    seg.momentary = NO;
    [seg addTarget:self action:@selector(someAction:) forControlEvents: UIControlEventValueChanged];
    [mainView addSubview:seg];

NOTE: To restate what I was trying to accomplish with this question: I want to set a UISegmentedControl's selected index via a variable dynamically, get the appropriate visual feedback, and check the selected index in a method, to make something happen depending on the selected index. See my answer below for a solution.

7条回答
叼着烟拽天下
2楼-- · 2020-08-09 08:55

The correct answer is the @arcady bob one at this link. I have posted an updated version for Swift 5, which I quote here:

yourSegmentedControl.selectedSegmentIndex = 0

yourSegmentedControl.sendActions(for: UIControl.Event.valueChanged)

If you use just the first line, the segmented will react accordingly graphically, but your IBAction associated with the segmented control won't be called. In a few words: the second line is like tapping on the segmented control. This is what I needed and what I was missing.

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ら.Afraid
3楼-- · 2020-08-09 08:57

This helps sort the selected segment, in terms of the visual feedbak, that is after programatically setting the selected segment this will tint the segments properly.

for (int i=0; i<[seg.subviews count]; i++)
{

    if ([[seg.subviews objectAtIndex:i] respondsToSelector:@selector(isSelected)] && [[seg.subviews objectAtIndex:i]isSelected])
    {
        [[seg.subviews objectAtIndex:i] setTintColor:[UIColor grayColor]];
    }
    if ([[seg.subviews objectAtIndex:i] respondsToSelector:@selector(isSelected)] && ![[seg.subviews objectAtIndex:i] isSelected])
    {
        [[seg.subviews objectAtIndex:i] setTintColor:[UIColor blackColor]];
    }
}
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在下西门庆
4楼-- · 2020-08-09 08:59

Change in viewDidLoad:

[seg setSelectedSegmentIndex:index];

you change use the index value as your wish.

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beautiful°
5楼-- · 2020-08-09 09:01

Swift 3.0

segmentedControl.selectedSegmentIndex = #your value#
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The star\"
6楼-- · 2020-08-09 09:08

From code, you can just do seg.selectedSegmentIndex = someDefaultIndex.

Whether you should set it in viewDidLoad: or not depends entirely on the structure of your application. For example, if your app is starting up and loading the view for the first time and needs to set the control to whatever value it had during the previous run of the app, then it definitely makes sense to do it there.

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孤傲高冷的网名
7楼-- · 2020-08-09 09:18

WARNING: This is not quite answering the question, but is closely related.

I had a similar issue. Most of the time my UISegmentedController worked fine. It has 4 segments, Off, 30, 60 and 120.

At random intervals (normally just prior to a release!!), the Off segment becomes un-selectable from the user interface. (I didn't try selecting it from code because that is not what I need to do and won't solve my problem.)

The solution is to delete that UISegmentedController from my XIB and replace it with a fresh (and exactly identical) one which then works fine.

I even CMD-C and CMD-V'd the offending UISegmentedController into another App's XIB. And the Off segment (i.e the one at index 0) was un-selectable in that XIB too.

This seems to be an issue with XCode.

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