Maximum sum of absolute differences dynamic progra

2020-07-27 05:37发布

We have an array of N elements. I have to choose K elements from this array(you can't take an element with index that is greater than the index of the element of the next one) in such a way that the sum abs(a1-a0)+abs(a2-a1)+...+(ak-ak-1) is maximized. My idea is 2d DP and goes like this: The solution that involves taking the n-th element while having taken k elements is the maximum of the solutions where element with index j smaller than i is the last one, j from k-1, j<i plus taking the abs(numbers[n]-numbers[j]). Here is my code. Where is my mistake?

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class SumOfAbsoluteDifferences {

    static int solve(int numbers[], int N, int K) {
        int[][] dp = new int[N][K];
        for (int i=0; i<N; i++) {
            for (int j=0; j<K; j++)
                dp[i][j] = 0;
        }

        int E = 1;

        for (int i=0; i<N; i++) {
            int maxx = -99999;

            for (int j=E-1; j<i; j++) {

                    if (dp[j][E-1] + Math.abs(numbers[i] - numbers[j]) > maxx) {
                        maxx = dp[j][E-1] + Math.abs(numbers[i] - numbers[j]);
                    }

            }
            if(E < K && E-1>=0) {
                dp[i][E-1] = maxx;
                E++;
            }

        }

        int maks = -9999;
        for (int i=0; i<N; i++) {
            if (dp[i][K-1] > maks)
                maks = dp[i][K-1];
        }
        return maks;
    }

    public static void main(String[] args) throws Exception {
        int i,j,k;

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(br.readLine());
        int N = Integer.parseInt(st.nextToken());
        int K = Integer.parseInt(st.nextToken());

        int numbers[] = new int[N];

        st = new StringTokenizer(br.readLine());
        for (i=0;i<N;i++) {
            numbers[i] = Integer.parseInt(st.nextToken());
        }

        int res = solve(numbers, N, K);
        System.out.println(res);

        br.close();

    }

}

For example this test case:

10 3 1 9 2 3 6 1 3 2 1 3

My code gives 0, it should be 16.

0条回答
登录 后发表回答