How to pass argument to java bash script? [duplica

Question

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Propagate all arguments in a bash shell script (11 answers)

Closed 5 years ago.

I have a simple bash script which runs my java program. Here is it:

run.sh

#!/bin/sh
java -jar target/my-jar-arch.jar

I want to pass arguments to this script, which must pass them to java program:

bash run.sh myArg -key 100

When I try to execute this line my app doesn't get any parameters. How can I fix it?

Answer 1

Change your invocation line to:

java -jar target/my-jar-arch.jar "$@"