Builder Pattern and Inheritance

Question

I have an object hierarchy that increases in complexity as the inheritance tree deepens. None of these are abstract, hence, all of their instances serve a, more or less sophisticated, purpose.

As the number of parameters is quite high, I would want to use the Builder Pattern to set properties rather than code several constructors. As I need to cater to all permutations, leaf classes in my inheritance tree would have telescoping constructors.

I have browsed for an answer here when I hit some problems during my design. First of, let me give you a simple, shallow example to illustrate the problem.

public class Rabbit
{
    public String sex;
    public String name;

    public Rabbit(Builder builder)
    {
        sex = builder.sex;
        name = builder.name;
    }

    public static class Builder
    {
        protected String sex;
        protected String name;

        public Builder() { }

        public Builder sex(String sex)
        {
            this.sex = sex;
            return this;
        }

        public Builder name(String name)
        {
            this.name = name;
            return this;
        }

        public Rabbit build()
        {
            return new Rabbit(this);
        }
    }
}

public class Lop extends Rabbit
{
    public float earLength;
    public String furColour;

    public Lop(LopBuilder builder)
    {
        super(builder);
        this.earLength = builder.earLength;
        this.furColour = builder.furColour;
    }

    public static class LopBuilder extends Rabbit.Builder
    {
        protected float earLength;
        protected String furColour;

        public LopBuilder() { }

        public Builder earLength(float length)
        {
            this.earLength = length;
            return this;
        }

        public Builder furColour(String colour)
        {
            this.furColour = colour;
            return this;
        }

        public Lop build()
        {
            return new Lop(this);
        }
    }
}

Now that we have some code to go on, imaging I want to build a Lop:

Lop lop = new Lop.LopBuilder().furColour("Gray").name("Rabbit").earLength(4.6f);

This call will not compile as the last chained call cannot be resolved, Builder not defining the method earLength. So this way requires that all calls be chained in a specific order which is very impractical, especially with a deep hierarchy tree.

Now, during my search for an answer, I came across Subclassing a Java Builder class which suggests using the Curiously Recursive Generic Pattern. However, as my hierarchy does not contain an abstract class, this solution will not work for me. But the approach relies on abstraction and polymorphism to function which is why I don't believe I can adapt it to my needs.

An approach I have currently settled with is to override all methods of the superclass Builder in the hierarchy and simply do the following:

public ConcreteBuilder someOverridenMethod(Object someParameter)
{
    super(someParameter);
    return this;
}

With this approach I can assure I am being returned an instance I can issue chain calls on. While this is not as worse as the Telescoping Anti-pattern, it is a close second and I consider it a bit "hacky".

Is there another solution to my problem that I am not aware of? Preferably a solution consistent with the design pattern. Thank you!

Answer 1

I did some experimenting and I found this to work quite nicely for me. Note that I prefer to create the actual instance at the start and the call all the setters on that instance. This is just a preference.

The main differences with the accepted answer is that

1. I pass a parameter that indicated the return type
2. There is no need for an Abstract... and a final builder.
3. I create a 'newBuilder' convenience method.

The code:

public class MySuper {
    private int superProperty;

    public MySuper() { }

    public void setSuperProperty(int superProperty) {
        this.superProperty = superProperty;
    }

    public static SuperBuilder<? extends MySuper, ? extends SuperBuilder> newBuilder() {
        return new SuperBuilder<>(new MySuper());
    }

    public static class SuperBuilder<R extends MySuper, B extends SuperBuilder<R, B>> {
        private final R mySuper;

        public SuperBuilder(R mySuper) {
            this.mySuper = mySuper;
        }

        public B withSuper(int value) {
            mySuper.setSuperProperty(value);
            return (B) this;
        }

        public R build() {
            return mySuper;
        }
    }
}

and then a subclass look like this:

public class MySub extends MySuper {
    int subProperty;

    public MySub() {
    }

    public void setSubProperty(int subProperty) {
        this.subProperty = subProperty;
    }

    public static SubBuilder<? extends MySub, ? extends SubBuilder> newBuilder() {
        return new SubBuilder(new MySub());
    }

    public static class SubBuilder<R extends MySub, B extends SubBuilder<R, B>>
        extends SuperBuilder<R, B> {

        private final R mySub;

        public SubBuilder(R mySub) {
            super(mySub);
            this.mySub = mySub;
        }

        public B withSub(int value) {
            mySub.setSubProperty(value);
            return (B) this;
        }
    }
}

and a subsub class

public class MySubSub extends MySub {
    private int subSubProperty;

    public MySubSub() {
    }

    public void setSubSubProperty(int subProperty) {
        this.subSubProperty = subProperty;
    }

    public static SubSubBuilder<? extends MySubSub, ? extends SubSubBuilder> newBuilder() {
        return new SubSubBuilder<>(new MySubSub());
    }

    public static class SubSubBuilder<R extends MySubSub, B extends SubSubBuilder<R, B>>
        extends SubBuilder<R, B> {

        private final R mySubSub;

        public SubSubBuilder(R mySub) {
            super(mySub);
            this.mySubSub = mySub;
        }

        public B withSubSub(int value) {
            mySubSub.setSubSubProperty(value);
            return (B)this;
        }
    }

}

To verify it fully works I used this test:

MySubSub subSub = MySubSub
        .newBuilder()
        .withSuper (1)
        .withSub   (2)
        .withSubSub(3)
        .withSub   (2)
        .withSuper (1)
        .withSubSub(3)
        .withSuper (1)
        .withSub   (2)
        .build();

Answer 2

If anyone still bumped into the same problem, I suggest the following solution, that conforms "Prefer composition over inheritance" design pattern.

Parent class

The main element of it is the interface that parent class Builder must implement:

public interface RabbitBuilder<T> {
    public T sex(String sex);
    public T name(String name);
}

Here is the changed parent class with the change:

public class Rabbit {
    public String sex;
    public String name;

    public Rabbit(Builder builder) {
        sex = builder.sex;
        name = builder.name;
    }

    public static class Builder implements RabbitBuilder<Builder> {
        protected String sex;
        protected String name;

        public Builder() {}

        public Rabbit build() {
            return new Rabbit(this);
        }

        @Override
        public Builder sex(String sex) {
            this.sex = sex;
            return this;
        }

        @Override
        public Builder name(String name) {
            this.name = name;
            return this;
        }
    }
}

The child class

The child class Builder must implement the same interface (with different generic type):

public static class LopBuilder implements RabbitBuilder<LopBuilder>

Inside the child class Builder the field referencing parentBuilder:

private Rabbit.Builder baseBuilder;

this ensures that parent Builder methods are called in the child, however, their implementation is different:

@Override
public LopBuilder sex(String sex) {
    baseBuilder.sex(sex);
    return this;
}

@Override
public LopBuilder name(String name) {
    baseBuilder.name(name);
    return this;
}

public Rabbit build() {
    return new Lop(this);
}

The constructor of Builder:

public LopBuilder() {
    baseBuilder = new Rabbit.Builder();
}

The constructor of builded child class:

public Lop(LopBuilder builder) {
    super(builder.baseBuilder);
}

Answer 3

Confronted with the same issue, I used the solution proposed by emcmanus at: https://community.oracle.com/blogs/emcmanus/2010/10/24/using-builder-pattern-subclasses

I'm just recopying his/her preferred solution here. Let say we have two classes, Shape and Rectangle. Rectangle inherits from Shape.

public class Shape {

private final double opacity;

public double getOpacity() {
    return opacity;
}

protected static abstract class Init<T extends Init<T>> {
    private double opacity;

    protected abstract T self();

    public T opacity(double opacity) {
        this.opacity = opacity;
        return self();
    }

    public Shape build() {
        return new Shape(this);
    }
}

public static class Builder extends Init<Builder> {
    @Override
    protected Builder self() {
        return this;
    }
}

protected Shape(Init<?> init) {
    this.opacity = init.opacity;
}

}

There is the Init inner class, which is abstract, and the Builder inner class, that is an actual implementation. Will be useful when implementing the Rectangle:

public class Rectangle extends Shape { private final double height;

public double getHeight() {
    return height;
}

protected static abstract class Init<T extends Init<T>> extends Shape.Init<T> {
    private double height;

    public T height(double height) {
        this.height = height;
        return self();
    }

    public Rectangle build() {
        return new Rectangle(this);
    }
}

public static class Builder extends Init<Builder> {
    @Override
    protected Builder self() {
        return this;
    }
}

protected Rectangle(Init<?> init) {
    super(init);
    this.height = init.height;
}

}

To instantiate the Rectangle:

new Rectangle.Builder().opacity(1.0D).height(1.0D).build();

Again, an abstract Init class, inheriting from Shape.Init, and a Build that is the actual implementation. Each Builder class implement the self method, which is responsible to return a correctly cast version of itself.

Shape.Init <-- Shape.Builder
     ^
     |
     |
Rectangle.Init <-- Rectangle.Builder

Answer 4

The following IEEE conference contribution Refined Fluent Builder in Java gives a comprehensive solution to the problem.

It dissects the original question into two sub-problems of inheritance deficiency and quasi invariance and shows how a solution to these two sub-problems opens for inheritance support with code reuse in the classical builder pattern in Java.

Answer 5

As you cannot use generics, now probably the main task is to somehow loosen typing. I don't know how you process those properties afterwards, but what if you used a HashMap for storing them as key-value pairs? So there will be just one set(key, value) wrapper method in the builder (or builder might not be necessary any more).

The downside would be additional type castings while processing the stored data.

If this case is too loose, then you could keep the existing properties, but have a general set method, which uses reflection and searches for setter method on the basis of 'key' name. Although I think reflection would be an overkill.

Answer 6

This form seems to nearly work. It is not very tidy but it looks like it avoids your issues:

class Rabbit<B extends Rabbit.Builder<B>> {

    String name;

    public Rabbit(Builder<B> builder) {
        this.name = builder.colour;
    }

    public static class Builder<B extends Rabbit.Builder<B>> {

        protected String colour;

        public B colour(String colour) {
            this.colour = colour;
            return (B)this;
        }

        public Rabbit<B> build () {
            return new Rabbit<>(this);
        }
    }
}

class Lop<B extends Lop.Builder<B>> extends Rabbit<B> {

    float earLength;

    public Lop(Builder<B> builder) {
        super(builder);
        this.earLength = builder.earLength;
    }

    public static class Builder<B extends Lop.Builder<B>> extends Rabbit.Builder<B> {

        protected float earLength;

        public B earLength(float earLength) {
            this.earLength = earLength;
            return (B)this;
        }

        @Override
        public Lop<B> build () {
            return new Lop<>(this);
        }
    }
}

public class Test {

    public void test() {
        Rabbit rabbit = new Rabbit.Builder<>().colour("White").build();
        Lop lop1 = new Lop.Builder<>().earLength(1.4F).colour("Brown").build();
        Lop lop2 = new Lop.Builder<>().colour("Brown").earLength(1.4F).build();
        //Lop.Builder<Lop, Lop.Builder> builder = new Lop.Builder<>();
    }

    public static void main(String args[]) {
        try {
            new Test().test();
        } catch (Throwable t) {
            t.printStackTrace(System.err);
        }
    }
}

Although I have successfully built Rabbit and Lop (in both forms) I cannot at this stage work out how to actually instantiate one of the Builder objects with it's full type.

The essence of this method relies on the cast to (B) in the Builder methods. This allow you to define the type of object and the type of the Builder and retain that within the object while it is constructed.

If anyone could work out the correct syntax for this (which is wrong) I would appreciate it.

Lop.Builder<Lop.Builder> builder = new Lop.Builder<>();