Why do we need an inserter function call when doin

2020-07-18 23:22发布

i need to make the call to the set_union function of STL like this:

set<int> a1, a2;

set_union(a1.begin(), a1.end(), a2.begin(), a2.end(), inserter(a1, a1.begin());

and not

set_union(a1.begin(), a1.end(), a2.begin(), a2.end(), a1.begin());

why is that so?

标签: c++ stl
1条回答
Ridiculous、
2楼-- · 2020-07-18 23:52

a1.begin() is simply not an output iterator. inserter(a1,a1.begin()) returns an output iterator which will invoke the set's insert function for each element. But I'm not even sure whether the first version is even correct. You iterate over the same set you insert new elements into. (!)

Since you deal with set<> objects already, why don't you simply write

a1.insert(a2.begin(),a2.end());

?

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