C compile error: “Variable-sized object may not be

Question

Why do I receive the error "Variable-sized object may not be initialized" with the following code?

int boardAux[length][length] = {{0}};

Answer 1

After declaring the array

int boardAux[length][length];

the simplest way to assign the initial values as zero is using for loop, even if it may be a bit lengthy

int i, j;
for (i = 0; i<length; i++)
{
    for (j = 0; j<length; j++)
        boardAux[i][j] = 0;
}

Answer 2

Simply declare length to be a cons, if it is not then you should be allocating memory dynamically

Answer 3

This gives error:

int len;
scanf("%d",&len);
char str[len]="";

This also gives error:

int len=5;
char str[len]="";

But this works fine:

int len=5;
char str[len]; //so the problem lies with assignment not declaration

You need to put value in the following way:

str[0]='a';
str[1]='b'; //like that; and not like str="ab";

Answer 4

For C++ separate declaration and initialization like this..

int a[n][m] ;
a[n][m]= {0};

Answer 5

You receive this error because in C language you are not allowed to use initializers with variable length arrays. The error message you are getting basically says it all.

6.7.8 Initialization

...

3 The type of the entity to be initialized shall be an array of unknown size or an object type that is not a variable length array type.

Answer 6

I am assuming that you are using a C99 compiler (with support for dynamically sized arrays). The problem in your code is that at the time when the compilers sees your variable declaration it cannot know how many elements there are in the array (I am also assuming here, from the compiler error that length is not a compile time constant).

You must manually initialize that array:

int boardAux[length][length];
memset( boardAux, 0, length*length*sizeof(int) );