How to delete an already written character in C++

Question

I'm trying to make a C++ program to read a password. I made the program to cout *, not the characters I write but my problem is when I want to delete character because they're wrong.
Example: My constant password is 12345
If I enter 1235 the program will show **** and I have to delete the last character. It's simple to remove it from the string but I want the last * to disappear from the console just as it happens when you introduce you windows password.
Is it possible? If it is, can someone explain how?

Answer 1

Sipmly write the '\b' character to stdout std::cout<<"\b". If you are using cpp or printf("\b") for pure C

Answer 2

printf("\b ");

This statement surely works because after the cursor goes one character back and space given in above printf statement will overwrite the printed character on console output.

Answer 3

When I am writting to console using putch function ( from conio.h ) to simulate backspace key simple

std::cout << '\b';

or

printf("\b ");

not works I have to write:

cout << '\b' << " " << '\b';

or

putch('\b');
putch(' ');
putch('\b');

Answer 4

Outputting the backspace character '\b' may help to move the output point back.

Specifically, outputting the string "\b \b" should blank out the last character output.

Answer 5

Try backspace \b or erase the whole line and print it again.