I have 20+ MySQL tables, prm_a
, prm_b
, ... with the same basic structure but different names, and I'd like to associate them with Django model classes without writing each one by hand. So, feeling ambitious, I thought I'd try my hand at using type()
as a class-factory:
The following works:
def get_model_meta_class(prm_name):
class Meta:
app_label = 'myapp'
setattr(Meta, 'db_table', 'prm_%s' % prm_name)
return Meta
prm_class_attrs = {
'foo': models.ForeignKey(Foo),
'val': models.FloatField(),
'err': models.FloatField(blank=True, null=True),
'source': models.ForeignKey(Source),
'__module__': __name__,
}
###
prm_a_attrs = prm_class_attrs.copy()
prm_a_attrs['Meta'] = get_model_meta_class('a')
Prm_a = type('Prm_a', (models.Model,), prm_a_attrs)
prm_b_attrs = prm_class_attrs.copy()
prm_b_attrs['Meta'] = get_model_meta_class('b')
Prm_b = type('Prm_b', (models.Model,), prm_b_attrs)
###
But if I try to generate the model classes as follows:
###
prms = ['a', 'b']
for prm_name in prms:
prm_class_name = 'Prm_%s' % prm_name
prm_class = type(prm_class_name, (models.Model,), prm_class_attrs)
setattr(prm_class, 'Meta', get_model_meta_class(prm_name))
globals()[prm_class_name] = prm_class
###
I get a curious Exception on the type()
line (given that __module__
is, in fact, in the prm_class_attrs
dictionary):
File ".../models.py", line 168, in <module>
prm_class = type(prm_class_name, (models.Model,), prm_class_attrs)
File ".../lib/python2.7/site-packages/django/db/models/base.py", line 79, in __new__
module = attrs.pop('__module__')
KeyError: u'__module__'
So I have two questions: what's wrong with my second approach, and is this even the right way to go about creating my class models?
OK - thanks to @Anentropic, I see that the items in my prm_class_attrs
dictionary are being popped away by Python when it makes the classes. And I now have it working, but only if I do this:
attrs = prm_class_attrs.copy()
attrs['Meta'] = get_model_meta_class(prm_name)
prm_class = type(prm_class_name, (models.Model,), attrs)
not if I set the Meta
class as an attribtue with
setattr(prm_class, 'Meta', get_model_meta_class(prm_name))
I don't really know why this is, but at least I have it working now.
You can use
./manage.py inspectdb
This will print out a python models file for the DB you're pointing at in yoursettings.py
DocumentationEDIT For dynamic models, try django-mutant or check out this link
The imediate reason is because you are not doing
prm_class_attrs.copy()
in yourfor
loop, so the__modules__
key is getting popped out of the dict on the first iterationAs for why this doesn't work:
setattr(prm_class, 'Meta', get_model_meta_class(prm_name))
...it's to do with the fact that Django's
models.Model
has a metaclass. But this is a Python metaclass which customises the creation of the model class and is nothing to do with theMeta
inner-class of the Django model (which just provides 'meta' information about the model).In fact, despite how it looks when you define the class in your
models.py
, the resulting class does not have aMeta
attribute:(You can access the
Meta
class directly, but aliased asMyModel._meta
)The model you define in
models.py
is really more of a template for a model class than the actual model class. This is why when you access a field attribute on a model instance you get the value of that field, not the field object itself.Django model inheritance can simplify a bit what you're doing: