Implementing a thread-safe, generic stack in C++ o

2020-07-13 08:43发布

In a recent interview, I was asked to implement a thread safe generic (i.e.template based) stack in C++, on linux machine.
I quickly came up with the following (It may have compilation errors).
I got through. The interviewer probably liked something in this implementation. Maybe the design part :)
Here are a few problems that this implementation may have:-
1. Incorrect implementation to indicate overflow/underflow. There is no overflow handling since I'm using STL vector as the underlying data structure. Should there be any such handling? Also, underflow (in Pop()) yields false as return value. Should it be done by throwing of an exception?
2. Implementation of PopElem routine. Is the below implementation correct?
3. No real use of top element.
4. Better timing between start of writer and reader thread.

Please make any comments/suggestions/improvements.
Thanks.

//Implementing a thread safe generic stack.

#include<pthread.h>
#include<iostream>
#include<vector>

using namespace std;

template<typename T>
class MyStack
{
public:
//interface
bool Push(T elem);
bool Pop(T& elem);
bool IsEmpty();

//constructor
MyStack() {
pthread_mutex_init(&lock);
top = 0;
}

//destructor
~MyStack() {
pthread_mutex_destroy(&lock);
}

private:
pthread_mutex_t lock;
int top;
vector<T> stack;

bool MyStack::Push(T elem);
bool MyStack::PopElem(T& elem);
}; //end of MyStack

template<typename T>
bool MyStack<T>::Push(T elem)
{
    pthread_mutex_lock(&lock);
    PushElem(elem);
    pthread_mutex_unlock(&lock);
}

template<typename T>
bool MyStack<T>::Pop(T& elem)
{
    pthread_mutex_lock(&lock);
    PopElem(elem);
    pthread_mutex_unlock(&lock);
}

template<typename T>
bool MyStack<T>::PushElem(T elem)
{
    stack.push_back(elem);
     top = stack.size();
}

template<typename T>
bool MyStack<T>::PopElem(T& elem)
{
   if(this.IsEmpty())
   {
        return false;
   }

   elem = stack.back(); //tricky, returns a reference to the last element
   stack.pop_back(); // is elem valid after this ??
   top = stack.size();
   return true;
}      


template<typename T>
bool MyStack<T>::IsEmpty()
{
    return stack.empty();
}


class MyStackTest
{
public:
  void Initialize() {
  pthread_init(&readerT);
  pthread_init(&writerT);
  }

  void Run() {
 pthread_create(writerT,0,writer,0); 
 pthread_create(readerT,0,reader,0);
 pthread_join(&writerT);
 pthread_join(&readerT);
}

private:
pthread_t readerT;
pthread_t writerT;
MyStack<int> stack;

void reader(void);
void writer(void);
};

void MyStackTest::writer() {
  for(int i=0;i<20;i++) {
      stack.Push(i);
      cout<<"\n\t Pushed element: "<<i;
   } //end for
}

void MyStackTest::reader() {
   int elem;
   while(stack.Pop(elem))
   {
     cout<<"\n\t Popped: "<<elem;
   }
}

int main()
{
    MyStackTest Test;

    Test.Run();
}

7条回答
淡お忘
2楼-- · 2020-07-13 09:37

Some issues:

  • I would implement a Locker class to claim & free the mutex using RAII
  • I would use std::stack
  • I would make the user of std::stack use the Locker to implement the locking policy - having a stack that locks itself is bad design, as the stack can't know how it is to be used
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