How do I check if values in a dictionary all have

Question

I have a dictionary, and I'm trying to check for the rare occurrence of all values having the same numerical value, say 1. How would I go about doing this in an efficient manner?

Answer 1

You can also try this:

>>> test
{'c': 3, 'b': 3, 'd': 3, 'f': 3}
>>> z=dict(zip(test.values(),test.keys()))
>>> z
{3: 'f'}
>>> len(z) == 1
True

Answer 2

Inspired by some of the discussion from this other question:

>>> def unanimous(seq):
...   it = iter(seq)
...   try:
...     first = next(it)
...   except StopIteration:
...     return True
...   else:
...     return all(i == first for i in it)
... 
>>> unanimous("AAAAAAAAAAAAA")
True
>>> unanimous("AAAAAAAAAAAAB")
False

Use unanimous to see if all dict values are the same:

>>> dd = { 'a':1, 'b':1, 'c':1 }
>>> print unanimous(dd.values())
True

Answer 3

You cannot have key*s* with the same value. This means that there is only one key in your dictionary, because every subsequent one will overwrite the previous. If you are concerned that all keys have the values which are one. Then you do something like this:

if set(your_dict.values()) == set([1]):
   pass

Answer 4

I will assume you meant the same value:

d = {'a':1, 'b':1, 'c':1}
len(set(d.values()))==1    # -> True

If you want to check for a specific value, how about

testval = 1
all(val==testval for val in d.values())   # -> True

this code will most often fail early (quickly)