How to get path of a python module ( not sys.execu

Question

I need to get Path for PyQt library in python program. Program is run as a script from another application, therefore my

sys.executable = 'D:/program files/visum/exe/visum115.exe

and I need my actual python path (and path for PyQt library module)

Path = C:\Python25\Lib\site-packages\PyQt4\plugins

im trying with

os.environ['PYTHONPATH']

but I'm not sure if it can be robust.

Regards!

PS. I need it to be able to plug plugins:

qApp.addLibaryPath('C:\Python25\Lib\site-packages\PyQt4\plugins')

Answer 1

you can try to load the module and after check for it's __file__ attribute to get the path of the .pyc file.

for example like this:

import MODULE, os
path = os.path.dirname(MODULE.__file__)

Regards, HTH!

Answer 2

What you're looking for is sys.path:

>>> import sys
>>> sys.path
 ['',
 '/usr/lib/python2.7/site-packages/virtualenvwrapper.github-0.1-py2.7.egg',
 '/usr/lib/python2.7/site-packages/pycharm-debug.egg',
 '/usr/lib/python2.7/site-packages/Fom-0.9.2-py2.7.egg',
 '/usr/lib/python2.7/site-packages/blinker-1.1-py2.7.egg',
 '/usr/lib/python2.7/site-packages/httplib2-0.6.0-py2.7.egg',
 '/usr/lib/python27.zip',
 '/usr/lib/python2.7',
 '/usr/lib/python2.7/plat-linux2',
 '/usr/lib/python2.7/lib-tk',
 '/usr/lib/python2.7/lib-old',
 '/usr/lib/python2.7/lib-dynload',
 '/usr/lib/python2.7/site-packages',
 '/usr/lib/python2.7/site-packages/Numeric',
 '/usr/lib/python2.7/site-packages/PIL',
 '/usr/lib/python2.7/site-packages/gst-0.10',
 '/usr/lib/python2.7/site-packages/gtk-2.0',
 '/usr/lib/python2.7/site-packages/setuptools-0.6c11.egg-info',
 '/usr/lib/python2.7/site-packages/wx-2.8-gtk2-unicode']