how to send url parameter in POST request without

2020-06-23 04:18发布

站内问答 / Django
724 2 4

I have to pass a parameter in url. I can't send it in as usual GET request the variable and value is shown in the address bar with the request. So, the end user can change the value for this variable value and send request which will be processed.

href="url=/admin/usermanagement/?flag=2

I want to send this hiding flag=2

now this goes as a GET request and it is seen in the address bar. Please give your suggestion if you have any idea on changing this to POST to hide and send the value.

2条回答
聊天终结者
2楼-- · 2020-06-23 04:24

You can use AJAX to get rid of forms entirely.

Just add this to your JavaScript:

function postTo(url, query) {
    var request = (XMLHttpRequest?new XMLHttpRequest():new ActiveXObject());
    request.open('POST', url, true);
    request.send(query);
}

Then call with something like this:

postTo('/admin/usermanagement/','flag=2');

Note that this will NOT reload the page. If you want to reload the page, use Borges' answer.

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不美不萌又怎样
3楼-- · 2020-06-23 04:36

You can still use a html form but "hide" it from the user:

<!DOCTYPE html>
<html>
    <body>
        <form id="myform" method="post" action="/">
            {% csrf_token %}
            <input type="hidden" name="flag" value="2" />
            <a href="#" onclick="document.forms[0].submit();return false;">Let's go!</a>
        </form>
    </body>
</html>

And the view:

def index(request):
    if request.method == 'POST':
        try:
            flag = request.POST['flag']
            # TODO use flag
        except KeyError:
            print 'Where is my flag?'

    return render_to_response('index.html', {},
        context_instance=RequestContext(request))
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