What regular expression will match valid internati

Question

I need to determine whether a phone number is valid before attempting to dial it. The phone call can go anywhere in the world.

What regular expression will match valid international phone numbers?

Answer 1

I have used this below:

^(\+|00)[0-9]{1,3}[0-9]{4,14}(?:x.+)?$

The format +CCC.NNNNNNNNNNxEEEE or 00CCC.NNNNNNNNNNxEEEE

Phone number must start with '+' or '00' for an international call. where C is the 1–3 digit country code,

N is up to 14 digits,

and E is the (optional) extension.

The leading plus sign and the dot following the country code are required. The literal “x” character is required only if an extension is provided.

Answer 2

This will work for international numbers;

C#:

@"^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$"

JS:

/^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$/

Answer 3

I use this one:

/([0-9\s\-]{7,})(?:\s*(?:#|x\.?|ext\.?|extension)\s*(\d+))?$/

Advantages: recognizes + or 011 beginnings, lets it be as long as needed, and handles many extension conventions. (#,x,ext,extension)

Answer 4

Here's an "optimized" version of your regex:

^011(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{0,14}$

You can replace the \ds with [0-9] if your regex syntax doesn't support \d.

Answer 5

public static boolean validateInternationalPhoneNumberFormat(String phone) {
    StringBuilder sb = new StringBuilder(200);

    // Country code
    sb.append("^(\\+{1}[\\d]{1,3})?");

    // Area code, with or without parentheses
    sb.append("([\\s])?(([\\(]{1}[\\d]{2,3}[\\)]{1}[\\s]?)|([\\d]{2,3}[\\s]?))?");

    // Phone number separator can be "-", "." or " "

    // Minimum of 5 digits (for fixed line phones in Solomon Islands)
    sb.append("\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?");

    // 4 more optional digits
    sb.append("\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?$");

    return Pattern.compile(sb.toString()).matcher(phone).find();
}

Answer 6

Try this, I do not know if there is any phone number longer than 12:

^(00|\+){1}\d{12}$