How Do i compress or encode the Elliptic curve pub

2020-06-16 04:48发布

I am developing Distributed digital signature that signs a document and send it through network to the Application Server.I am using socket programming in java to do it. I think the public key should be encoded or compressed i.e the x and y values are somehow represented as a single binary data and saved in a public registry or network.But i don't know how to do it in java.

        // I have class like this 
           public class CryptoSystem{                  

               EllipticCurve ec = new EllipticCurve(new P192());

               //-------------------
               //--------------------

               public ECKeyPair generatekeyPair()
               {
                  return ECKeyPair(ec);

               }


            }    
        // i don't think i have problem in the above


    CryptoSystem crypto = new CryptoSystem();
    ECKeyPair keyPair = crypto.generateKeyPair();
    BigInteger prvKey = keyPair.getPrivateKey();
    ECPoint pubKey = keyPair.getPublicKey();
     // recommend me here to  compress and send it  the public key to a shared network.

I want to know how to encode the public key and domain parameters, so that the verifier of the signature will decode it to use it.because when you send them over the network to the verifier u gonna have to encode the as a single byte array.i am no using Bouncy Castle Provider. The whole implementation of ECDSA algorithm is my project

2条回答
叛逆
2楼-- · 2020-06-16 05:13

Elliptic curve points are almost always encoded using the encoding specified in X9.62.

It is optional to use point compression. It is trivial to encode using point compression, but decoding a compressed point needs a bit more work, so unless you really need to save the extra bytes, I would not bother. Let me know if you need it, and I will add the details. You can recognize X9.62 encoded points with point compression by the first byte, which will be 0x02 or 0x03.

Encoding without point compression is really simple: start with a 0x04 (to indicate no compression). Then follow with first the x coordinate, then the y coordinate, both zero-padded on the left up to the size in bytes of the field:

int qLength = (q.bitLength()+7)/8;
byte[] xArr = toUnsignedByteArray(x);
byte[] yArr = toUnsignedByteArray(y);
byte[] res = new byte[1+2*qLength];
res[0] = 0x04;
System.arraycopy(xArr, 0, res, qLength - xArr.length, xArr.length);
System.arraycopy(yArr, 0, res, 2* qLength - yArr.length, nLength);

Decoding this is of course trivial.

查看更多
够拽才男人
3楼-- · 2020-06-16 05:19

I'm pretty sure that the BC implementation uses X9.63 encoding, so these would be rather standardized encodings. You will need to add the Bouncy Castle provider to your JRE (Security.addProvider(new BouncyCastleProvider()), see the bouncy documentation.

public static void showECKeyEncodings() {

    try {
        KeyPairGenerator kp = KeyPairGenerator.getInstance("ECDSA");
        ECNamedCurveParameterSpec ecSpec = ECNamedCurveTable
                .getParameterSpec("prime192v1");
        kp.initialize(ecSpec);
        KeyPair keyPair = kp.generateKeyPair();

        PrivateKey privKey = keyPair.getPrivate();
        byte[] encodedPrivKey = privKey.getEncoded();
        System.out.println(toHex(encodedPrivKey));

        PublicKey pubKey = keyPair.getPublic();
        byte[] encodedPubKey = pubKey.getEncoded();
        System.out.println(toHex(encodedPubKey));

        KeyFactory kf = KeyFactory.getInstance("ECDSA");
        PublicKey pubKey2 = kf.generatePublic(new X509EncodedKeySpec(encodedPubKey));
        if (Arrays.equals(pubKey2.getEncoded(), encodedPubKey)) {
            System.out.println("That worked for the public key");
        }

        PrivateKey privKey2 = kf.generatePrivate(new PKCS8EncodedKeySpec(encodedPrivKey));
        if (Arrays.equals(privKey2.getEncoded(), encodedPrivKey)) {
            System.out.println("That worked for the private key");
        }

    } catch (GeneralSecurityException e) {
        throw new IllegalStateException(e);
    }

}
查看更多
登录 后发表回答