How can I use mySQL replace() to replace strings i

2019-01-01 10:23发布

We have a database that has a bunch of records with some bad data in one column, in which an embedded editor escaped some stuff that shouldn't have been escaped and it's breaking generated links.

I want to run a query to replace the bad characters in all the records, but can't figure out how to do it. I found the replace() function in MySQL, but how can I use it inside a query?

For example, what would be the correct syntax if I wanted to replace the string &lt; with an actual less-than angle bracket (<) in all records that have &lt; in the articleItem column? Can it be done in a single query (i.e. select and replace all in one swoop), or do I have to do multiple queries? Even if it's multiple queries, how do I use replace() to do the replace on the value of a field on more than one record?

标签: mysql replace
4条回答
几人难应
2楼-- · 2019-01-01 10:40

you can write a stored procedure like this:

CREATE PROCEDURE sanitize_TABLE()

BEGIN

#replace space with underscore

UPDATE Table SET FieldName = REPLACE(FieldName," ","_") WHERE FieldName is not NULL;

#delete dot

UPDATE Table SET FieldName = REPLACE(FieldName,".","") WHERE FieldName is not NULL;

#delete (

UPDATE Table SET FieldName = REPLACE(FieldName,"(","") WHERE FieldName is not NULL;

#delete )

UPDATE Table SET FieldName = REPLACE(FieldName,")","") WHERE FieldName is not NULL;

#raplace or delete any char you want

#..........................

END

In this way you have modularized control over table.

You can also generalize stored procedure making it, parametric with table to sanitoze input parameter

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大哥的爱人
3楼-- · 2019-01-01 10:43

At a very generic level

UPDATE MyTable

SET StringColumn = REPLACE (StringColumn, 'SearchForThis', 'ReplaceWithThis')

WHERE SomeOtherColumn LIKE '%PATTERN%'

In your case you say these were escaped but since you don't specify how they were escaped, let's say they were escaped to GREATERTHAN

UPDATE MyTable

SET StringColumn = REPLACE (StringColumn, 'GREATERTHAN', '>')

WHERE articleItem LIKE '%GREATERTHAN%'

Since your query is actually going to be working inside the string, your WHERE clause doing its pattern matching is unlikely to improve any performance - it is actually going to generate more work for the server. Unless you have another WHERE clause member that is going to make this query perform better, you can simply do an update like this:

UPDATE MyTable
SET StringColumn = REPLACE (StringColumn, 'GREATERTHAN', '>')

You can also nest multiple REPLACE calls

UPDATE MyTable
SET StringColumn = REPLACE (REPLACE (StringColumn, 'GREATERTHAN', '>'), 'LESSTHAN', '<')

You can also do this when you select the data (as opposed to when you save it).

So instead of :

SELECT MyURLString From MyTable

You could do

SELECT REPLACE (MyURLString, 'GREATERTHAN', '>') as MyURLString From MyTable

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十年一品温如言
4楼-- · 2019-01-01 11:01

Check this

UPDATE some_table SET some_field = REPLACE("Column Name/String", 'Search String', 'Replace String')

Eg with sample string:

UPDATE some_table SET some_field = REPLACE("this is test string", 'test', 'sample')

EG with Column/Field Name:

UPDATE some_table SET some_field = REPLACE(columnName, 'test', 'sample')
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余生无你
5楼-- · 2019-01-01 11:06
UPDATE some_table SET some_field = REPLACE(some_field, '&lt;', '<')
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