There are a lot of questions and answers on stackoverflow on the subject, but no one that helps.
I have a schema with optional value:
{
"type" : "record",
"name" : "UserSessionEvent",
"namespace" : "events",
"fields" : [ {
"name" : "username",
"type" : "string"
}, {
"name" : "errorData",
"type" : [ "null", "string" ],
"default" : null
}]
}
And I'm trying deserialize json w/o this field:
{
"username" : "2271AE67-34DE-4B43-8839-07216C5D10E1",
"errorData" : { "string":"070226AC-9B91-47CE-85FE-15AA17972298"}
}
using code:
val reader = new GenericDatumReader[GenericRecord](schema)
val decoder = DecoderFactory.get().jsonDecoder(schema, json)
reader.read(null, decoder)
and I got: org.apache.avro.AvroTypeException: Expected field name not found: errorData
The only way that works is json
{
"username" : "2271AE67-34DE-4B43-8839-07216C5D10E1",
"errorData" : null
}
Is there a way to deserialize json w/o this field?
Another question: when this field is here, I should write
{
"username" : "2271AE67-34DE-4B43-8839-07216C5D10E1",
"errorData" : { "string":"070226AC-9B91-47CE-85FE-15AA17972298"}
}
Is there a way to deserialize a "normal" json:
{
"username" : "2271AE67-34DE-4B43-8839-07216C5D10E1",
"errorData" : "070226AC-9B91-47CE-85FE-15AA17972298"
}
?
case 1 is working fine in java .
for case 2 Your schema is defined for union. You can update you schema as below to deserialize json.