using php __DIR__

2020-06-09 01:33发布

I'm trying to create a config.php file that defines a global variable which contains the path to a directory called "projectfiles". The idea is that any file can point to this directory regardless of where it is in the file tree.

Can I use __DIR__ for this? Would someone be willing to give me an example of how this might work? I was thinking of something like the following:

I want to define an directory here: in the /config.php file

$projectfiles = __DIR__("projectfiles/")

Then I want a library file to be able to use this variable in /venders/library/generalfunctions.php file

include("../../../config.php");
$file = $projectfiles/testfile.php

Suggestions?

标签: php constants
2条回答
在下西门庆
2楼-- · 2020-06-09 02:08

It looks like the architecture of this application is less than optimal, but without knowing more, I can't comment on that..

I suggest defining it as a constant so that it can't be altered and is available no matter the scope.

define('PROJECTFILES',__DIR__.'/projectfiles/');

Assuming:
/config.php
/projectfiles/include_me.php

include(PROJECTFILES.'include_me.php');

Keep in mind that __DIR__ will reference the directory that config.php is in. If config.php is the parent folder of projectfiles then the above will work.

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Viruses.
3楼-- · 2020-06-09 02:17

__DIR__ is certainly what you are looking for. Use it to provide relative paths for required files. I would highly suggest using require_once or include_once for all library files.

if( !defined( __DIR__ ) ) define( __DIR__, dirname(__FILE__) );
require_once( __DIR__ . '/../../../config.php');
.
.
.
// you code here

Using the first line ensures you wont run into trouble with PHP 5.2 and back. This will allow you to include files based on directory structure instead of relative to the script called. Many frameworks use dirname(__FILE__) instead, but it is rather wasteful to run more than once. It is better to just add it somewhere with a check.

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