In Java, how do I parse XML as a String instead of

Question

I have the following code:

DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(xmlFile);

How can I get it to parse XML contained within a String instead of a file?

Answer 1

One way is to use the version of parse that takes an InputSource rather than a file

A SAX InputSource can be constructed from a Reader object. One Reader object is the StringReader

So something like

parse(new InputSource(new StringReader(myString))) may work. 

Answer 2

Convert the string to an InputStream and pass it to DocumentBuilder

final InputStream stream = new ByteArrayInputStream(string.getBytes(StandardCharsets.UTF_8));
DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
builder.parse(stream);

EDIT
In response to bendin's comment regarding encoding, see shsteimer's answer to this question.

Answer 3

I have this function in my code base, this should work for you.

public static Document loadXMLFromString(String xml) throws Exception
{
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    InputSource is = new InputSource(new StringReader(xml));
    return builder.parse(is);
}

also see this similar question

Answer 4

You can use the Scilca XML Progession package available at GitHub.

XMLIterator xi = new VirtualXML.XMLIterator("<xml />");
XMLReader xr = new XMLReader(xi);
Document d = xr.parseDocument();

Answer 5

I'm using this method

public Document parseXmlFromString(String xmlString){
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    InputStream inputStream = new    ByteArrayInputStream(xmlString.getBytes());
    org.w3c.dom.Document document = builder.parse(inputStream);
    return document;
}

Answer 6

javadocs show that the parse method is overloaded.

Create a StringStream or InputSource using your string XML and you should be set.