How can I get filename of current working cs file

Question

This question already has answers here:

Print the source filename and linenumber in C# (5 answers)

Closed 7 years ago.

Suppose I am working on Welcome.cs file. In the constructor I want to print "Welcome". However, If I put the same code in HelloWorld.cs, it should print HellowWorld. How do I do that?

Answer 1

If you want to get the class name, you can use Reflection technique.

eg:

Type classType = yourObject.GetType();

you can get the name of the class from

classType.Name

Answer 2

How to print

[current file name - method name - line number] ?

private static void Log(string text,
                        [CallerFilePath] string file = "",
                        [CallerMemberName] string member = "",
                        [CallerLineNumber] int line = 0)
{
    Console.WriteLine("{0}_{1}({2}): {3}", Path.GetFileName(file), member, line, text);
}

Test:

Log("Test");

Output:

Program.cs_Main(11): Test

Answer 3

if I've understood correctly, try this.GetType().Name

Answer 4

You can try

string thisFile = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileName(); 

Answer 5

Try this to get the file name:

string currentFile = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileName(); 

To get the current line:

int currentLine = new System.Diagnostics.StackTrace(true).GetFrame(0).GetFileLineNumber();