How to make a function wait until a callback has b

2019-01-01 09:53发布

I have a simplified function that looks like this:

function(query) {
  myApi.exec('SomeCommand', function(response) {
    return response;
  });
}

Basically i want it to call myApi.exec, and return the response that is given in the callback lambda. However, the above code doesn't work and simply returns immediately.

Just for a very hackish attempt, i tried the below which didn't work, but at least you get the idea what i'm trying to achieve:

function(query) {
  var r;
  myApi.exec('SomeCommand', function(response) {
    r = response;
  });
  while (!r) {}
  return r;
}

Basically, what's a good 'node.js/event driven' way of going about this? I want my function to wait until the callback gets called, then return the value that was passed to it.

11条回答
梦醉为红颜
2楼-- · 2019-01-01 10:18

Since node 4.8.0 you are able to use the feature of ES6 called generator. You may follow this article for deeper concepts. But basically you can use generators and promises to get this job done. I'm using bluebird to promisify and manage the generator.

Your code should be fine like the example below.

const Promise = require('bluebird');

function* getResponse(query) {
  const r = yield new Promise(resolve => myApi.exec('SomeCommand', resolve);
  return r;
}

Promise.coroutine(getResponse)()
  .then(response => console.log(response));
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墨雨无痕
3楼-- · 2019-01-01 10:24

If you don't want to use call back then you can Use "Q" module.

For example:

function getdb() {
    var deferred = Q.defer();
    MongoClient.connect(databaseUrl, function(err, db) {
        if (err) {
            console.log("Problem connecting database");
            deferred.reject(new Error(err));
        } else {
            var collection = db.collection("url");
            deferred.resolve(collection);
        }
    });
    return deferred.promise;
}


getdb().then(function(collection) {
   // This function will be called afte getdb() will be executed. 

}).fail(function(err){
    // If Error accrued. 

});

For more information refer this: https://github.com/kriskowal/q

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怪性笑人.
4楼-- · 2019-01-01 10:28

Note: This answer should probably not be used in production code. It's a hack and you should know about the implications.

There is the uvrun module (updated for newer Nodejs versions here) where you can execute a single loop round of the libuv main event loop (which is the Nodejs main loop).

Your code would look like this:

function(query) {
  var r;
  myApi.exec('SomeCommand', function(response) {
    r = response;
  });
  var uvrun = require("uvrun");
  while (!r)
    uvrun.runOnce();
  return r;
}

(You might alternative use uvrun.runNoWait(). That could avoid some problems with blocking, but takes 100% CPU.)

Note that this approach kind of invalidates the whole purpose of Nodejs, i.e. to have everything async and non-blocking. Also, it could increase your callstack depth a lot, so you might end up with stack overflows. If you run such function recursively, you definitely will run into troubles.

See the other answers about how to redesign your code to do it "right".

This solution here is probably only useful when you do testing and esp. want to have synced and serial code.

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怪性笑人.
5楼-- · 2019-01-01 10:29

One way to achieve this is to wrap the API call into a promise and then use await to wait for the result.

// let's say this is the API function with two callbacks,
// one for success and the other for error
function apiFunction(query, successCallback, errorCallback) {
    if (query == "bad query") {
        errorCallback("problem with the query");
    }
    successCallback("Your query was <" + query + ">");
}

// myFunction wraps the above API call into a Promise
// and handles the callbacks with resolve and reject
function apiFunctionWrapper(query) {
    return new Promise((resolve, reject) => {
        apiFunction(query,(successResponse) => {
            resolve(successResponse);
        }, (errorResponse) => {
            reject(errorResponse)
        });
    });
}

// now you can use await to get the result from the wrapped api function
// and you can use standard try-catch to handle the errors
async function businessLogic() {
    try {
        const result = await apiFunctionWrapper("query all users");
        console.log(result);

        // the next line will fail
        const result2 = await apiFunctionWrapper("bad query");
    } catch(error) {
        console.error("ERROR:" + error);
    }
}

// call the main function
businessLogic();

Output:

Your query was <query all users>
ERROR:problem with the query
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不流泪的眼
6楼-- · 2019-01-01 10:31

supposing you have a function:

var fetchPage(page, callback) {
   ....
   request(uri, function (error, response, body) {
        ....
        if (something_good) {
          callback(true, page+1);
        } else {
          callback(false);
        }
        .....
   });


};

you can make use of callbacks like this:

fetchPage(1, x = function(next, page) {
if (next) {
    console.log("^^^ CALLBACK -->  fetchPage: " + page);
    fetchPage(page, x);
}
});
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人气声优
7楼-- · 2019-01-01 10:33

To me it worked to use

JSON.parse(result)['key']

on the result I expected. This may not be "super general", but in the end "JSON.parse" managed the waiting for the asyncronous call, whilst result['key'] didn't.

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