How to instantiate a type dynamically using reflec

2020-05-25 03:43发布

I need to instatiate a C# type dynamically, using reflection. Here is my scenario: I am writing a base class, which will need to instantiate a certain object as a part of its initialization. The base class won't know what type of object it is supposed to instantiate, but the derived class will. So, I want to have the derived class pass the type to the base class in a base() call. The code looks something like this:

public abstract class MyBaseClass
{
    protected MyBaseClass(Type myType)
    {
         // Instantiate object of type passed in 
         /* This is the part I'm trying to figure out */
    }
}

public class MyDerivedClass : MyBaseClass
{
    public MyDerivedClass() : base(typeof(Whatever))
    {
    }
}

In other words, the base class is delegating to its derived type the choice of the object type to be instantiated.

Can someone please assist?

标签: c# reflection
3条回答
在下西门庆
2楼-- · 2020-05-25 04:13
在下西门庆
3楼-- · 2020-05-25 04:27

You're looking for Activator.CreateInstance

object instance = Activator.CreateInstance(myType);

There are are various overloads of this method that can take constructor arguments or other information to find the type (such as names in string form)

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在下西门庆
4楼-- · 2020-05-25 04:30

You might want to use generics instead:

public abstract class MyBaseClass<T> where T : new()
{
    protected MyBaseClass()
    {
        T myObj = new T();
         // Instantiate object of type passed in 
         /* This is the part I'm trying to figure out */
    }
}

public class MyDerivedClass : MyBaseClass<Whatever>
{
    public MyDerivedClass() 
    {
    }
}

The where T : new() is required to support the new T() construct.

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