How do I write a script to determine if a file is older than 30 minutes in /bin/sh?
Unfortunately does not the stat
command exist in the system. It is an old Unix system, http://en.wikipedia.org/wiki/Interactive_Unix
Perl is unfortunately not installed on the system and the customer does not want to install it, and nothing else either.
Here's my variation on
find
:Find always returns status code
0
unless it fails; however,egrep
returns1
is no match is found`. So this combination passes if that file is older than 10 minutes.Try it:
Should print 0 and then 1 after the file's path.
My function using this:
For those like myself, who don't like back ticks, based on answer by @slebetman:
You can use the find command.
For example, to search for files in current dir that are older than 30 min:
You can read up about the find command HERE
The following gives you the file age in seconds:
which means this should give a true/false value (1/0) for files older than 30 minutes:
30*60
-- 60 seconds in a minute, don't precalculate, let the CPU do the work for you!What do you mean by older than 30 minutes: modified more than 30 minutes ago, or created more than 30 minutes ago? Hopefully it's the former, as the answers so far are correct for that interpretation. In the latter case, you have problems since unix file systems do not track the creation time of a file. (The
ctime
file attribute records when the inode contents last changed, ie, something likechmod
orchown
happened).If you really need to know if file was created more than 30 minutes ago, you'll either have to scan the relevant part of the file system repeatedly with something like
find
or use something platform-dependent like linux's inotify.If you're writing a sh script, the most useful way is to use
test
with the already mentioned stat trick:Note that
[
is a symbolic link (or otherwise equivalent) totest
; seeman test
, but keep in mind thattest
and[
are also bash builtins and thus can have slightly different behavior. (Also note the[[
bash compound command).