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I am attempting to use BeautifulSoup to parse through a DOM tree and extract the names of authors. Below is a snippet of HTML to show the structure of the code I'm going to scrape.
<html>
<body>
<div class="list-authors">
<span class="descriptor">Authors:</span>
<a href="/find/astro-ph/1/au:+Lin_D/0/1/0/all/0/1">Dacheng Lin</a>,
<a href="/find/astro-ph/1/au:+Remillard_R/0/1/0/all/0/1">Ronald A. Remillard</a>,
<a href="/find/astro-ph/1/au:+Homan_J/0/1/0/all/0/1">Jeroen Homan</a>
</div>
<div class="list-authors">
<span class="descriptor">Authors:</span>
<a href="/find/astro-ph/1/au:+Kosovichev_A/0/1/0/all/0/1">A.G. Kosovichev</a>
</div>
<!--There are many other div tags with this structure-->
</body>
</html>
My point of confusion is that when I do soup.find, it finds the first occurrence of the div tag that I'm searching for. After that, I search for all 'a' link tags. At this stage, how do I extract the authors names from each of the link tags and print them out? Is there a way to do it using BeautifulSoup or do I need to use Regex? How do I continue iterating over every other other div tag and extract the authors names?
import re
import urllib2,sys
from BeautifulSoup import BeautifulSoup, NavigableString
html = urllib2.urlopen(address).read()
soup = BeautifulSoup(html)
try:
authordiv = soup.find('div', attrs={'class': 'list-authors'})
links=tds.findAll('a')
for link in links:
print ''.join(link[0].contents)
#Iterate through entire page and print authors
except IOError:
print 'IO error'
Since
linkis already taken from an iterable, you don't need to subindexlink-- you can just dolink.contents[0].print link.contents[0]with your new example with two separate<div class="list-authors">yields:So I'm not sure I understand the comment about searching other divs. If they are different classes, you will either need to do a separate
soup.findandsoup.findAll, or just modify your firstsoup.find.just use findAll for the divs link you do for the links
for authordiv in soup.findAll('div', attrs={'class': 'list-authors'}):