ASP.NET Identity remove column from AspNetUsers ta

2020-05-18 03:50发布

When I use ASP.NET Identity first code approach, I want to generate columns in AspNetUsers table in my own way. I don't need to have stored multiple columns with null values. I just need columns Id, SecurityStamp and UserName. Only post, that I've found is here: AspNet Identity 2.0 Email and UserName duplication , but it is still unsloved (due to error in Santosh comment).

So can anybody tell my how to solve this?

EDIT: Is it even possible to delete some of these columns/properties?

Thanks

4条回答
我欲成王,谁敢阻挡
2楼-- · 2020-05-18 04:10

The short answer is no, not without rolling your own implementation. Or you can wait for them to open source asp.net identity on codeplex. Who knows how long that will take.

The default implementation includes all of those unused columns (see below).

// Summary:
//     Default EntityFramework IUser implementation
//
// Type parameters:
//   TKey:
//
//   TLogin:
//
//   TRole:
//
//   TClaim:
public class IdentityUser<TKey, TLogin, TRole, TClaim> : IUser<TKey>
    where TLogin : Microsoft.AspNet.Identity.EntityFramework.IdentityUserLogin<TKey>
    where TRole : Microsoft.AspNet.Identity.EntityFramework.IdentityUserRole<TKey>
    where TClaim : Microsoft.AspNet.Identity.EntityFramework.IdentityUserClaim<TKey>
{
    // Summary:
    //     Constructor
    public IdentityUser();

    // Summary:
    //     Used to record failures for the purposes of lockout
    public virtual int AccessFailedCount { get; set; }
    //
    // Summary:
    //     Navigation property for user claims
    public virtual ICollection<TClaim> Claims { get; }
    //
    // Summary:
    //     Email
    public virtual string Email { get; set; }
    //
    // Summary:
    //     True if the email is confirmed, default is false
    public virtual bool EmailConfirmed { get; set; }
    //
    // Summary:
    //     User ID (Primary Key)
    public virtual TKey Id { get; set; }
    //
    // Summary:
    //     Is lockout enabled for this user
    public virtual bool LockoutEnabled { get; set; }
    //
    // Summary:
    //     DateTime in UTC when lockout ends, any time in the past is considered not
    //     locked out.
    public virtual DateTime? LockoutEndDateUtc { get; set; }
    //
    // Summary:
    //     Navigation property for user logins
    public virtual ICollection<TLogin> Logins { get; }
    //
    // Summary:
    //     The salted/hashed form of the user password
    public virtual string PasswordHash { get; set; }
    //
    // Summary:
    //     PhoneNumber for the user
    public virtual string PhoneNumber { get; set; }
    //
    // Summary:
    //     True if the phone number is confirmed, default is false
    public virtual bool PhoneNumberConfirmed { get; set; }
    //
    // Summary:
    //     Navigation property for user roles
    public virtual ICollection<TRole> Roles { get; }
    //
    // Summary:
    //     A random value that should change whenever a users credentials have changed
    //     (password changed, login removed)
    public virtual string SecurityStamp { get; set; }
    //
    // Summary:
    //     Is two factor enabled for the user
    public virtual bool TwoFactorEnabled { get; set; }
    //
    // Summary:
    //     User name
    public virtual string UserName { get; set; }
}
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成全新的幸福
3楼-- · 2020-05-18 04:16

Actually you can, just configure your entity on OnModelCreating of your context class.

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Entity<IdentityUser>().Ignore(u => u.AccessFailedCount);
    //and so on...
}

Or if your application has a separate file for each configuration (wich is what i recommend), you can do like this:

public class ApplicationUserEntityTypeConfiguration : EntityTypeConfiguration<ApplicationUser>
{
    public ApplicationUserEntityTypeConfiguration()
    {
        Ignore(p => p.AccessFailedCount);
        //And so on..
    }
}
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家丑人穷心不美
4楼-- · 2020-05-18 04:30

I know this might not be completely related, but if you simply want to exclude columns in JSON responses all you have to do is place [JsonIgnore] above the property. I use Entity so by default the (encrypted) password is included in the model. Even if the password is encrypted you still don't want the end-user to get it. One way to maintain access to that property without including it in a response is shown below.

In the below example the Password field would be removed from the Json response because we added [JsonIgnore] to the model.

public int Id { get; set; }
public string Email { get; set; }

[JsonIgnore]
public string Password { get; set; } // <--- Removed from JSON response

public string FirstName { get; set; }
public string MiddleName { get; set; }
public string LastName { get; set; }
public string PhoneNumber { get; set; }
public bool Active { get; set; }

Here is a sample JSON response.

{
  "id": 1,
  "email": "ddavis@example.com",
  "firstName": "Daniel",
  "middleName": "Cool-Guy",
  "lastName": "Davis",
  "phoneNumber": "12055550000",
  "active": true
}
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家丑人穷心不美
5楼-- · 2020-05-18 04:36

Actually you can ignore the fields, just you need to configure your entity OnModelCreating within your context Class as:

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
        base.OnModelCreating(modelBuilder);
        modelBuilder.Entity<IdentityUser>().Ignore(c => c.AccessFailedCount)
                                           .Ignore(c=> c.LockoutEnabled)
                                           .Ignore(c=>c.LockoutEndDateUtc)
                                           .Ignore(c=>c.Roles)
                                           .Ignore(c=>c.TwoFactorEnabled);//and so on...

        modelBuilder.Entity<IdentityUser>().ToTable("Users");//to change the name of table.

}
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