I have a string containing comma separated keywords. For Example:
$keywords = 'keyword1, keyword2, keyword3';
My Table schema, named tbl_address
is like this ( simplified ) :
id INT(11) PRIMARY KEY, AUTO INCREMENT
address VARCHAR(250) NOT NULL
Assume I have to use MySQLi
in PHP ( not PDO
).
Here is my current approach:
$result = array();
$keyword_tokens = explode(',', $keywords);
foreach($keyword_tokens as $keyword) {
$keyword = mysqli_real_escape_string(trim($keyword));
$sql = "SELECT * FROM tbl_address WHERE address LIKE'%$keyword%'";
// query and collect the result to $result
// before inserting to $result, check if the id exists in $result.
// if yes, skip.
}
return $result;
This approach works, but inefficient in performance. If there are a lot of keywords, it will make a lot queries.
My question is, is there a better way to achieve the same goal ? i.e. what is the simplest way to return all records with the address containing the ANY of the keywords ?
You only need an 'OR', nothing else...
edit: Just to be sure you also trim the keywords
Also, you should also pass the db resource link to the
mysqli_real_escape_string()
function...Try WHERE IN clause:
Successfully tested on MySQL 5.1.