Show the password with EditText

Question

I use an EditText to enter password. And a CheckBox to show password or not. Below function is the part:

public void ShowPassword() {
    if (cb.isChecked()) {
        password.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
    } else {
        password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
    }
}

When it checked, it show password. But when it not checked, it does show stars. How to modify it to show star while the cb is not checked?

Answer 1

okay:

To show readeable text:

setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD)

To "star" the password:

setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD)

But why? The Type_Text_Variation_Password set it to stars, but why does only adding Type_Claas_Text revive the visibel password?
I would have thought that Type_Text_Variation_VISIBLE_Password comes into play ...

Answer 2

This will work -

public void ShowPassword() {
    if (cb.isChecked()) {
        password.setInputType(InputType.TYPE_CLASS_TEXT);
    } else {
        password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
    }
}

Answer 3

The Password Visibility Toggle feature has been added to support library version 24.2.0 enabling you to toggle the password straight from the password field without the need for a CheckBox.

You can make that work basically by setting an inputType of password on the TextInputEditText. Here's how to do that:

<android.support.design.widget.TextInputLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content">

        <android.support.design.widget.TextInputEditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="@string/password"
            android:inputType="textPassword"/>
</android.support.design.widget.TextInputLayout>

Answer 4

instead of visible password, can you try with TYPE_TEXT_VARIATION_NORMAL

public void ShowPassword() {
password.setInputType((cb.isChecked()) ? 
InputType.TYPE_TEXT_VARIATION_NORMAL : InputType.TYPE_TEXT_VARIATION_PASSWORD;
}

Answer 5

This is not an answer,

Answer already given and accepted..

I just want to clarify about 129

password.setInputType(129);

is Actually,

password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

'|' is not a pipe, it's a bitwise OR. It takes two binary numbers and if either of the bits of equal value are 1,

How this relates to the input type: Each of the InputTypes are actually just ints. TYPE_CLASS_TEXT is 1, and TYPE_TEXT_VARIATION_PASSWORD is 128 (or 10000000).

Perform a bitwise OR on them:

00000001

10000000

------------

10000001 which is 129.

Try entering input.setInputType(129); instead, you'll see it'll work. :)

Answer 6

This might help you mate

checkBox.setOnCheckedChangeListener(new OnCheckedChangeListener() {

    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        // checkbox status is changed from uncheck to checked.
        if (!isChecked) {
            // show password
            editText.setTransformationMethod(PasswordTransformationMethod.getInstance());
        } else {
            // hide password
            editText.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
    }
});