log first 10 in git

Question

Two questions:

1. How to show the first 10 commit in git from beginning to end. (no branch)
2. How the specify the commit index and log it. (show the second or third)

I know that git use parent to link the commit, it's easy to log the commit from end to start. like: git log HEAD~10

But i need to query from the start to end, is it possible?

Answer 1

i would use below simple syntax command;

git log -10 --oneline

Answer 2

Simply log everything reverse -1 means list one log

git log  --reverse -1

Answer 3

the best result comes with combination of both best answers:

git log --pretty=oneline -10

Answer 4

In case someone wants more than just git one-line log:

git log --reverse | awk 'NR>1 {print last} {last=$0}; /^commit/ && ++c==11{exit}'

where the 11 at the end should be set to 1 more than the number of commits you want.

As here points out git log --reverse -n 10 doesn't work as you need it to. (I suppose it would need to be non-commutative to give you the ability to chose the first 10 commits in reverse order or the last 10 commits

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Answer 5

Simply log everything with one line format and tail the output:

git log  --pretty=oneline | tail -n 10 

Answer 6

git log -10

Would show 10 latest commits matching the revision spec (a missing spec means "all commits").

See manpage:

git help log

section Commit Limiting

-<number>, -n <number>, --max-count=<number>
    Limit the number of commits to output.