jQuery delete all table rows except first

Question

Using jQuery, how do I delete all rows in a table except the first? This is my first attempt at using index selectors. If I understand the examples correctly, the following should work:

$(some table selector).remove("tr:gt(0)");

which I would read as "Wrap some table in a jQuery object, then remove all 'tr' elements (rows) where the element index of such rows is greater than zero". In reality, it executes without generating an error, but doesn't remove any rows from the table.

What am I missing, and how do I fix this? Of course, I could use straight javascript, but I'm having so much fun with jQuery that I'd like to solve this using jQuery.

Answer 1

Consider a table with id tbl: the jQuery code would be:

$('#tbl tr:not(:first)').remove();

Answer 2

I think this is more readable given the intent:

$('someTableSelector').children( 'tr:not(:first)' ).remove();

Using children also takes care of the case where the first row contains a table by limiting the depth of the search.

If you had an TBODY element, you can do this:

$("someTableSelector > tbody:last").children().remove();

If you have THEAD or TFOOT elements you'll need to do something different.

Answer 3

If it were me, I'd probably boil it down to a single selector:

$('someTableSelector tr:not(:first)').remove();

Answer 4

This worked in the following way in my case and working fine

$("#compositeTable").find("tr:gt(1)").remove();

Answer 5

To Remove all rows, except the first one (except header), use the below code:

$("#dataTable tr:gt(1)").remove();

Answer 6

This works perfectly

$("#myTable tbody").children( 'tr:not(:first)' ).html("");