Note: I have corrected the variable differences and it does print the query from the first set but it returns nothing from the second set. If I use the second set only it works.
In the code below, I have some_array which is array of array the array contains text like name. So @some_array= ([sam, jon, july],[Mike, Han,Tommy],[angie, sita, lanny]); Now when I querying the list like 'sam jon july' first and 'mike han tommy' . Only the execute return the result from the first list others is undef. I don't know why any help will be appreciated.
my $pointer;
my $db = $db->prepare_cached("
begin
:pointer := myFun(:A1);
end;
") or die "Couldn't prepare stat: " . $db->errstr;
$db->bind_param_inout(":pointer",\$pointer,0,{ ora_type => ORA_RSET });
for (my $i=0; $i < @some_array ; $i++) {
my @firstarray = @{$some_array[$i]};
my $sql = lc(join(" ", @firstarray));
print "<pre>$sql</pre>\n";
$db->bind_param(":A1",$sql);
$db->execute();
print "<pre>".Dumper($db->execute())."</pre>\n";
}
Just like everyone told you on the last question you asked, initialize your array with parentheses, not nested brackets.
not
You would also benefit tremendously from including
at the top of all of your programs. That would catch the strange way you are trying to initialize
@some_array
, and it would catch your inconsistent usage of@sql
and@query
. update and$sdh
and$db
and$dbh
.