Echo in for loop

2020-05-10 08:35发布

站内问答 / PHP
480 2 5

This is my code:

<?php
$date = 2015-02-30;
$year = substr($date, 0, 4);
$month = substr($date, 5, 2);
$day = substr($date, 8, 2);
?>

<select>

<?php
for ($i=1; $i < 31; $i++) { ?>
    <option value="<?php echo $i; ?>" <?php if($day === $i){ echo "selected"; }; ?>><?php echo $i; ?></option>
<?php } ?>

</select>

For the option, the number 4 should be selected. Why doesn't it work? Thanks

Sorry, I already had this in a select statement

EDIT: See the code edit above. Maybe because the

2条回答
Root（大扎）
2楼-- · 2020-05-10 09:07

After your edit, it looks like this is your main problem:

$date = 2015-02-30;

This is not what you think it is. It should be quoted like this:

$date = '2015-02-30';

Otherwise, $date is a not a string, it's a math expression that evaluates to (int) 1983, so substr($date, 8, 2); will evaluate to false, not 30, and then obviously your option won't be selected.

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祖国的老花朵
3楼-- · 2020-05-10 09:24

You need to wrap your code in a select statement!

An option statement wont work without the select tag around it:

<html>

<body>

<select>  <!-- Start the select statement -->

<!-- Your Code -->
<?php
$num = 4;
for ($i=1; $i < 10; $i++)
{
    ?>
    <option value="<?php echo $i; ?>" <?php if($num === $i){ echo "selected"; }; ?>><?php echo $i; ?></option>
    <?php
}
?>
<!-- End your code -->

</select> <!-- End the select statement -->

</body>

</html>
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