Class operators

2020-05-10 08:26发布

I'm having a problem to make the code:

void main(){
     Matrix c(rows,cols);//rows & cols are int numbers
     c[0][0]=2//the line that I'm having a problem to do the operator
}

//My class defined like this: 
class Matrix{
public:
     Matrix(int rows,int cols): rows(rows), cols(cols){
         mat= new double*[cols];
         for( int i=0; i<rows;i++){
             *mat=new double[i];
         }
     }
private:
     int rows,cols;
     double **mat;
};

How can I make an operator that will help me to do the line that I'm having a problem with?

2条回答
家丑人穷心不美
2楼-- · 2020-05-10 09:11

Don't dynamically allocate in two dimensions like that. It's poison for your cache, and completely pointless. I see it all the time and I wish I didn't! Make yourself a nice std::vector<double> of size rows*cols instead.

Anyway, the trick to permit [width][height] is a proxy class. Have your operator[] return an instance of a class that has its own operator[] to do the second-level lookup.

Something like this:

#include <iostream>
#include <vector>

struct Matrix
{
    Matrix(const size_t columns, const size_t rows)
       : columns(columns)
       , rows(rows)
       , data(columns*rows, 0)
    {}

    size_t index(const size_t x, const size_t y) const
    {
        return x + y*columns;
    }

    double& at(const size_t x, const size_t y)
    {
        return data[index(x, y)];
    }

    double at(const size_t x, const size_t y) const
    {
        return data[index(x, y)];
    }

    template <bool Const>
    struct LookupHelper
    {
        using ParentType = std::conditional_t<Const, const Matrix, Matrix>;
        using ReturnType = std::conditional_t<Const, double, double&>;

        LookupHelper(ParentType& parent, const size_t x) : parent(parent), x(x) {}

        ReturnType operator[](const size_t y)
        {
            return parent.data[parent.index(x, y)];
        }

        const ReturnType operator[](const size_t y) const
        {
            return parent.data[parent.index(x, y)];
        }

    private:
        ParentType& parent;
        const size_t x;
    };

    LookupHelper<false> operator[](const size_t x)
    {
        return {*this, x};
    }

    LookupHelper<true> operator[](const size_t x) const
    {
        return {*this, x};
    }

private:
    const size_t columns, rows;
    std::vector<double> data;
};

int main()
{
    Matrix m(42, 3);
    m[15][3] = 1;
    std::cout << m[15][3] << '\n';
}

(In reality, you'd want to make it moveable and it could doubtlessly be tidied up a bit.)

Certainly, switching to operator() or a .at(width, height) member function is a lot easier…

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姐就是有狂的资本
3楼-- · 2020-05-10 09:15

There are no operator [][], but operator[]. So that one should return something for which you can use [] too (pointer or proxy class).

In your case, you might simply do:

double* operator[](int i) { return mat[i]; }
const double* operator[](int i) const { return mat[i]; }

For more complicated cases, you have to return a proxy class.

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