Finding the minimum value of int numbers in an arr

Question

I'm trying to find the minimum value of numbers in an array but it doesn't always work out properly. This is the code I wrote:

        for (int i=0; i < arr.length; i++ ) {
        min = arr[i];
        for (j=0; j < arr.length; j++) {
        if (arr[j] < arr[0]) {
            min = arr[j];
         }
        }
    }   

Can someone correct me please?

Answer 1

If arr is an array of non-primitive numerics, I'd recommend

java.util.Collections.min(java.util.Arrays.asList(arr));

as that will be simpler to maintain. There's some justification in reverting to hand-coding if you need to pull the minimum and maximum out at the same time but I'd advise against hand-coding loops if there's a library function available.

In any case, you ought to check arr != null and the existence of a zeroth element.

Answer 2

int min = arr[0];
for(int num : arr) {
    if (num < min){
        min = num;
    }
}

min now contains minimum value.

Answer 3

One option is sort your array and get the first element:

import java.util.Arrays;

...

int ints[] = {30,5,7,4,10};
Arrays.sort(ints);

int min = ints[0];
int max = ints[ints.length - 1];

Answer 4

There's no need for the outer loop, it only runs once and you don't use i anyway. why do you have it?

For the inner loop, you need to compare against the minimum value. Right now you are comparing it against the first element in the array, which is not necessarily the minimum value.

min = arr[0];
for (j=0; j < arr.length; j++) {
    if (arr[j] < min) {  //<---fix is here
        min = arr[j];
    }
}

Also you could start the loop at 1, since you don't need to compare arr[0] against itself (it was just assigned to min)

Answer 5

TRY this:

int min = arr[0];
    for(int j=1;j<arr.length;j++)
    {
            if(min>arr[j])
            {
                min= arr[j];
            }
    }
    System.out.println("min no is "+min);

Answer 6

A way to do it would be using the java.util.Arrays class:

Example:

public class ArraySort {
public static void main(String[] args) {
    int[] array = {12, 4, 6, 1, 56, 21, 77};
    Arrays.sort(array);
    System.out.println(array[0]);
}
}

From the Java doc, Arrays.sort(int[]) sort the specified array into ascending numerical order.

So the output here prints 1.