Collections.sort() error

2020-04-25 23:36发布

I am trying to sort a list of type A named BinOrder in class B according to Class A's int r.

However i am receiving this error for the line Collections.sort(BinOrder);

The method sort(List<T>) in the type Collections is not applicable for the arguments (ArrayList<A>)

Class A:

public class A{
int s; 
int r;

public A(int si, int ri) {
    s=si;
    r= ri;
 }
}

Class B:

import java.util.ArrayList;
import java.util.Collections;


public class B implements Comparable<A> {



    public Iterator<A> randomMethodName(int a) {
        ArrayList<A> BinOrder = new ArrayList<A>();
                A a = new A(1,3)
                A a2 = new A(1,4)

                BinOrder.add(a);
                BinOrder.add(a2);
        }

        // sort array in increasing order of r
        Collections.sort(BinOrder);
        return BinOrder;
    }

    @Override
    public int compareTo(A list) {

        return null;
    }
}

2条回答
我想做一个坏孩纸
2楼-- · 2020-04-25 23:54

To be able to use the single-argument version of Collection.sort() on an ArrayList of A, A should implement the Comparable interface:

public class A implements Comparable<A> {
  ...
  @Override
  int compareTo(A rhs) {
    ...
  }
}
查看更多
一夜七次
3楼-- · 2020-04-26 00:06

Here's the signature of Collections.sort :

public static <T extends Comparable<? super T>> void sort(List<T> list)

A must implement Comparable for this method.

You try to pass BinOrder to this method, when BinOrder is of type ArrayList<A>, but since A does not implement Comparable<A>, it doesn't fit the signature of the method.

Either change A to implement Comparable, or use the sort method that accepts a Comparator :

public static <T> void sort(List<T> list, Comparator<? super T> c)
查看更多
登录 后发表回答