remove xml tags with XSLT

2019-01-15 15:48发布

I have the following xml file:

<xfa:data>
  <form1>
    <Page1>
    <Page2>
    <contractInfo> ... </contractInfo>
    <paymentInfo> ... </paymentInfo>
  </form1>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
</xfa:data>

I want to remove every ocurrence of the commercialType, userList and officesList nodes, so my output would be :

<xfa:data>
  <form1>
    <Page1>
    <Page2>
    <contractInfo> ... </contractInfo>
    <paymentInfo> ... </paymentInfo>
  </form1>
</xfa:data>

How could I do that using XSLT?

Thank you

标签: xml xslt
2条回答
聊天终结者
2楼-- · 2019-01-15 16:22

This transformation produces the desired results:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="commercialType|userList|officesList"/>
</xsl:stylesheet>
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够拽才男人
3楼-- · 2019-01-15 16:38

Identity transformation plus <xsl:template match="commercialType" priority="10"/>.

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